**New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Fractions Chapter 5J Solution**

**(1)** 1 4/5

= 9/5

**(2)** Anil spends on supplies 2/5 of his budget

Anil spends on advertising 2/12 of his budget

Anil spends on taxes 2/15 of his budget

LCM of 5, 12 and 25 = 300

2×60/5×60 = 120/300

2×25/12×35 = 100/300

2×12/25×12 = 24/300

Ans/ Anil spend more on advertising.

**(3)** Sumer ran in 2 days = (1/3 + 3 1/4) km

= 1/3 + 13/4

= 4+39/12

= 43/12

= 3 7/12

Ans. On two days Sumer ran 3 7/12 km.

**(4)** Tails appear = (100 – 55) times

= 45

In fraction = 45/100

Ans. Total tails are 9/20

**(5)** Crows was standing = 1 – (3/4 + 1/8)

= 1 – (6 + 1/8)

= 1 – 7/8

= 8 – 7 / 8

= 1/8

Ans. fraction of crowd standing is 1/8

**6)** sales occured in morning = 3/8

Sales occured in afternoon 7/10

Sales occured in evening = 3/16

LCM of 8, 16, 19 = 80

3×10/8×10 = 30/80

7×8/10×8 = 56/80

3×5/16×5 = 15/80

Ans. During afternoon most of her sales occured.

**(7)** Fraction remains = 1 – (1/5 + 1/3 + 1/4)

= 1 – 12+20+15/60

= 1 – 47/60

= 13/60

∴ Pages remains = 240 x 13/60

= 52

Ans. Fraction remains to be read is 13/60 pages remains to be read are 52.

**(8)** Shekhar jogs = (1/4) + 2 1/8 + 1 1/20) km

= (5/4 + 17/8 + 21/20) km

= 50 + 85 + 42 / 40

= 177/40

∴ (5 – 177/40) km

= 200-177/40

= 23/40 km

= 575 m

ans. One round is 23/40 km or 575 m less than 5 km.

**(9)** Sudhir walked 3/5 km

∴ Prem walked = (3/5 – 7/20) km

= 12 – 7 / 20

= 5/20

= 1/4 km

Rohan walked = (1/4 + 5/8)

= 2+5/8

= 7/8

Ans – Rohan walked 7/8 km.

**10)** Jouney remains = {1 – (1/8 + 2/5 + 3/10)}

= {1 – 5+16+12/40}

= {1 – 33/40}

= 40-33/40

= 7/40 km

Whole distance is 80 km

∴ I ride before breakfast = (80 x 1/8) km

= 10 km

∴ I ride between breakfast and lunch = (80 x 2/5) km

= 32 km

∴ I ride between lunch and tea = (80 x 3/10) km

= 24 km

Ans – Journey remains 7/40 km

I ride 10 km before breakfast, 32 km between breakfast and lunch, 24 km between lunch and tea.