New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14C Solution (1) (a) Area = (17 X 10) cm2 = 170 cm2 (b) Area = (5 X 8) m2 = 40 m2 (c) Area = (200 X 120) m2 = 24000 m2 (d) Area = 152 m2 = 225 m2 […]

### Category: Class 6

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Basic Constructions Chapter 13 Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Basic Constructions Chapter 13 Solution Process: (a) At first I draw a ray BC. Write B as centre and any convenient radius I draw an arc, cutting BC at Q. With Q as center and same radius I draw another arc to cut the first […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14B Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14B Solution Rules of Rectangle: Area of Rectangle = Length x Breadth If in Question there are Length is given and Area is given, you have to find Breadth. Then Breadth Area/Length If in Question there are Breadth is given and […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14A Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14A Solution (1) (a) Perimeter = (3 + 5 + 6 + 2 + 7) unit = 23 (b) DE = (10 – 6) unit = 4 EF = (8 + 7) unit = 15 ∴ Perimeter = (8 + 6 […]

## ML Aggarwal CBSE Solutions Class 6 Math Fourteenth Chapter Practical Geometry Exercise 14.3

ML Aggarwal CBSE Solutions Class 6 Math 14th Chapter Practical Geometry Exercise 14.3 (1) Draw an angle of 80o and make a copy of it using ruler and compass. (2) Draw an angle of measure 127o and construct its bisector. (3) Draw <POQ = 64o. Also draw its line of symmetry. Solution: (4) Draw a […]

## ML Aggarwal CBSE Solutions Class 6 Math Fourteenth Chapter Practical Geometry Exercise 14.1

ML Aggarwal CBSE Solutions Class 6 Math 14th Chapter Practical Geometry Exercise 14.1 (1) Construct a circle of radius: (i) 2 cm (ii) 3.5 cm (2) With the same centre O, draw two circles of radii 2.6 cm 4.1 cm. Solution: (3) Draw any circle and mark points A, B and C such that – […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8F Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8F Solution (1) Cost of 20 m of cloth = RS 1600 Cost of 1 m of cloth = RS 1600/20 = RS 80 ∴ Cost of 28 m of cloth = RS (80X28) = RS 2240 Ans – […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8E Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8E Solution (2) (a) Product of extremes = 14 X 9 = 126 Product of means = 7 X 18 = 126 Since product of extremes = product of means ∴ given numbers are in proportion (b) Product of […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8D Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8D Solution (4) The ratio = 54:45 = 6:5 (5) The ratio = 104:130 = 4:5 (6) The factor = 125/100 = 5/4 (7) The factor = 60/72 = 5/6 (8) The ratio = (1+ 1/10) : 1 = […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8C Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8C Solution (3) Let, the total students of the school be x Sum of the ratio = 3+2 = 5 According to statement, x X 3/5 = 600 Or, 3x = 600 X 5 Or, x = 600X5/3 ∴ […]