New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14C Solution (1) (a) Area = (17 X 10) cm2 = 170 cm2 (b) Area = (5 X 8) m2 = 40 m2 (c) Area = (200 X 120) m2 = 24000 m2 (d) Area = 152 m2 = 225 m2 […]

### Category: Composite Mathematics Solution

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Basic Constructions Chapter 13 Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Basic Constructions Chapter 13 Solution Process: (a) At first I draw a ray BC. Write B as centre and any convenient radius I draw an arc, cutting BC at Q. With Q as center and same radius I draw another arc to cut the first […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14B Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14B Solution Rules of Rectangle: Area of Rectangle = Length x Breadth If in Question there are Length is given and Area is given, you have to find Breadth. Then Breadth Area/Length If in Question there are Breadth is given and […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14A Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14A Solution (1) (a) Perimeter = (3 + 5 + 6 + 2 + 7) unit = 23 (b) DE = (10 – 6) unit = 4 EF = (8 + 7) unit = 15 ∴ Perimeter = (8 + 6 […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8F Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8F Solution (1) Cost of 20 m of cloth = RS 1600 Cost of 1 m of cloth = RS 1600/20 = RS 80 ∴ Cost of 28 m of cloth = RS (80X28) = RS 2240 Ans – […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8E Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8E Solution (2) (a) Product of extremes = 14 X 9 = 126 Product of means = 7 X 18 = 126 Since product of extremes = product of means ∴ given numbers are in proportion (b) Product of […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8D Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8D Solution (4) The ratio = 54:45 = 6:5 (5) The ratio = 104:130 = 4:5 (6) The factor = 125/100 = 5/4 (7) The factor = 60/72 = 5/6 (8) The ratio = (1+ 1/10) : 1 = […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8C Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8C Solution (3) Let, the total students of the school be x Sum of the ratio = 3+2 = 5 According to statement, x X 3/5 = 600 Or, 3x = 600 X 5 Or, x = 600X5/3 ∴ […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8B Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8B Solution (1) (a) 2/3, 3/2 LCM of 3, 2 = 6 2X2/3X2 = 4/6 3X3/2X3 = 6/6 Ans – 3/2 > 2/3 (b) 3:5, 1:2 LCM of 5/2 = 10 3X2/5X2 = 6/10 1X5/2X5 = 5/10 ∴ 3:5 […]

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8A Solution

New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Ratio Proportion and Unitary Method Chapter 8A Solution (1) (a) (i) Number of roses/Number of lilies = 10/12 = 5/6 ∴ The ratio of roses to lilies = 5:6 (ii) Number of daisies/Number of roses = 8/10 = 4/5 ∴ The ratio of daisies to […]