# New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Fractions Chapter 5I Solution

## New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Fractions Chapter 5I Solution

(1) (a) 5 2/3 + 3 3/4

= 17/3 + 15/4

= 68 + 45 / 12  [LCD of 3, 4 = 12]

= 113/12

= 9 5/12

(b) 3 1/5 + 9 7/10

= 16/5 + 97/10

= 32 + 97 / 10  [LCD of 5, 10 = 10]

= 129/10

= 12 9/10

(c) 19 7/10 + 12 5/8

= 197/10 + 101/8

= 788+505/40 [LCD of 10, 8 = 40]

= 1293/40

= 32 13/’40

(d) 2 15/22 + 3 20/33

= 59/22 + 119/33

= 177+238/66 [LCD of 22, 33 = 66]

= 415/66

= 6 19/66

(2) (a) 7 5/6 – 4 1/3

= 47/6 – 13/3

= 47 – 26 / 6

= 21/6

= 7/2

= 3 1/2

(b) 13 3/5 – 7 7/15

= 68/5 – 112/15 [LCD of 5, 15 = 15]

= 204-112/15

= 92/15

= 6 2/15

(c) 3 3/4 – 1 2/5

= 15/4 – 17/5

= 75-28/20 [LCD of 4, 5 = 20]

= 47/20

= 2 7/20

(d) 2 3/4 – 1 5/21

= 31/14 – 26/21 [LCD of 14, 21 = 42]

= 93 – 52/42

= 41/42

(3) 7 1/3 + 4 5/8 + 2 1/6

= 22/3 + 37/8 + 13/6

= 176 + 111 + 52 / 24 [LCD of 3, 8 , 6 = 24]

= 339/24

= 14 1/8

(4) 2 1/2 + 3 3/4 – 1 7/8 + 5 2/3

= 5/2 + 15/4 – 15/8 + 17/3

= 60 + 90 – 45 + 136/24 [LCD of 2, 4, 8, 3 = 24]

= 241/24

= 10 1/24

(5) 4 1/8 – (1 1/4 + 2 1/2)

= 33/8 – (5/4 + 5/2) [LCD of 4, 2 = 4]

= 33/8 – (5 + 10 / 4)

= 33/8 – 15/4

= 33 – 30 / 8 [LCD of 8, 4 = 8]

= 3 / 8

(6) 6 1/5 – (4 3/10 – 1 1/2)

= 31/5 – (43/10 – 3/2)

= 31/5 – (43-15/10) [LCD of 10, 2 = 10]

= 31/5 – 28/10

= 62 – 28 / 10 [LCD of 5, 10 = 10]

= 34/10

= 3 2/5

Updated: May 31, 2021 — 2:11 pm