**New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Fractions Chapter 5B Solution**

**(1)** A -> 3/5

B -> 7/5

= 1 2/5

**(2)** 3/10 = G

1 4/10 = A

7/10 = H

2 1/10 = B

1 9/10 = P

**(3)** A -> 2/8

B -> 5/8

C -> 11/8 = 1 3/8

D -> 15/8 = 1 7/8

E -> 21/8 = 2 5/8

F -> 25/8 = 2 5/8

F -> 25/8 = 3 1/8

G -> 29/8 = 3 5/8

H -> 38/8 = 4 6/8

**4)** a) 1 3/10 = A

b) 3 1/10 = E

c) 11/10 = B

d) 1 6/10 = H

e) 2 4/10 = C

f) 3 5/10 = K

g) 7/10 = G

h) 2 9/10 = F

i) 3 8/10 = D