ML Aggarwal CBSE Solutions Class 8 Math 6th Chapter Percentage and its Applications Exercise 6.2
(1) (i) CP = 400/-
SP = 468/-
Profit = 468 – 400 = 68
Profit % = Profit/CP X 100
= 68/400 X 100
= 17 % (Ans)
(ii) C.P. = 13600/-
S.P. = 12104/-
Loss = 13600 – 12104 = 1496/-
Loss % = Loss/CP X100
= 1496/13600 X100
= 11 % (Ans)
(2) S.P = RS 1636.25
Gain = RS 96.25
CP = 163.25 – 96.25 [∵Cp = Sp – gain]
= Rs 1540.00
∴ gain % = gain/CP X100
96.25/154.00 X100
= 6.25% (Ans)
(3) SP = 770/-
Loss = 110/-
∴ CP = SP + Loss [∵ Loss = CP – SP]
= 770 + 110
= 880/-
∴ Loss % = Loss/CP X100
= 110/880 X100
= 12.5 % (Ans)
(4) 1 dozen = 12 egg
Price of 1 dozen (12 egg) = 9.60/-
∴ Price of 25 dozen (25X12) = 9.60X25
∴ Price of 25 dozen (300 eggs) = 240/-
∴ Price of 300 eggs = 240/-
∴ Price of 30 eggs = 240/300 X30
= 24/-
∴ Price of 1 eggs = 24/30 = 0.8/-
No of remaining egg = (300 – 30)
= 270 eggs
Given, she sold 270 egg = 270X1
= 270/-
Her gain = 270 – 240 = 30/-
Gain % = 30/240 X100
= 25/2 = 12.5%
(5) CP = 20000/-
Repairing cost = 1400/-
∴ Total expenditure = 20000 + 1400
= 21400/-
Profit = 20%
SP = 21400X120/100
= 25,680/-
(6) Cost price 1 bicycle = 1200/-
∴ Cost price of 200 bicycle = 1200X200 = 240000/-
Transportation cost of 200 bicycle = 200X30
= 6000/-
∴ Total expenditure = 240000 + 6000 + 4000
= 250000/-
SP of 200 bicycle = 200X1350 = 270000/-
∴ Profit of bicycle = 270000 – 250000
∴ Profit % = 20000/240000 X100 = 25/3 = 8.33%
(7) Let, SP = x
CP = 90% of x
= 90x/100 = 9x/10
∴ Profit = x – 9x/10 = 10x – 9x/10 = x/10
∴ Profit% = x/10/(9x/10) X100
= 33.3% (Ans)
(8) CP of notebooks @ 4 = 35/-
CP of notebooks @ 1 = 35/4 /-
SP of notebooks @ 5 = 58/-
∴ SP of notebooks @ 1 = 58/5 /-
∴ gain = 58/5 – 35/4
= 232 – 175/20
= 57/20
(i) gain % = 57/20/(35/4) X100
= 57/20 X 4/35 X100
= 228/7 = 32 4/7 % (Ans)
(ii) Let, x no of note books he should sell.
CP of 1 note book = 35/4 /-
∴ CP of x note book = 35x/4 /-
SP of 1 note book = 58/5 /-
∴ SP of x note book = 58x/5 /-
According to question –
58x/5 – 35x/4 = 171
Or, 232x – 175x/20 = 171
Or, 57x = 171X20
Or, x = 171X20/57
Or, x = 60
∴ 60 no of notebooks he should sell (Ans)
(9) CP of no of 3 bananas = 1 /-
∴ CP of no of 1 bananas = 1/3 /-
SP of no of 4 bananas = 1 /-
∴ SP of no of 1 bananas = 1/4 /-
∴ Loss = 1/3 – 1/4
= 4-3/12 = 1/12 /-
∴ Loss % = 1/12/(1/3) X100
= 1/12 X3X100
= 25%
(10) 1 dozen = 12 eggs
CP of 12 eggs = 36 /-
∴ CP of 1 egg = 36/12 = 3 /-
Profit = 50 %
∴ SP of 1 egg = 150X3/100 = 9/2
= 4.50 /- (Ans)
(11) CP of Laptop = 40000/-
CP of mobile = 24000/-
CP of total transaction = 8%
Loss for mobile = 12%
∴ SP of laptop = 40000X108/100
= 43200/-
∴ SP of total whole transaction = 43200 + 21120
= 64320/-
Profit = 64320 – 64000/-
= 320/-
= 1/2 = 0.5% (Ans)
(12) CP of 1st gadget = 44000/-
CP of 2nd gadget = 44000/-
Loss for 1st gadget = 12%
Profit for 2nd gadget = 10%
SP of 1st gadget = 88X44000/100
= 38720/-
SP of 2nd gadget = 110X44000/100
= 48,400/-
Total CP of two gadget = 44000+44000
= 88000/-
Total SP of two gadget = 38720+48400
= 87120/-
∴ Overall loss = 88000 – 87120
= 880/-
(13) (i) SP = 450/-
Loss = 10%
CP = 450X100/90
= 500/- (Ans)
(ii) SP = 690/-
Profit = 15%
CP = 690X100/115
= 600/- (Ans)
(14) SP1 = 3920/-
Gain = 12%
CP = 3920X100/112
= 3500/-
Again SP2 = 4375/-
∴ Profit = 4375 – 3500
= 875/-
∴ Profit% = 875/3500 X100
= 25% (Ans)
(16) SP1 of sweater = x
∴ Loss = 5%
∴ CP = 100x/95
Now, SP2 when profit 15% = (100x/95) X115/100
= 100x X 115/100 X 25
= 115x/95 = 23x/19
According to question –
X + 260 = 23x/19
Or, 19x + 4940 = 23x
Or, 23x – 19x = 4940
Or, 4x = 4940
Or, x = 4940/4
Or, x = 1235
∴ SP1= 1235
∴ CP = 100 X 1235/95 = 1300/-
(17) Let, SP1 = x
Loss = 8%
∴ CP = 100x/92
Now, SP2 when profit would be 12% = 112X (100x/92)/100
= 112 X 100x / 100X92
= 112x/92
According to question –
X + 150 = 112x/92
Or, 92x + 13800 = 112x
Or, 112x – 92x = 13800
Or, 20x = 13800
Or, x = 13800/20
Or, x = 690
∴ SP2 = 690/-
