Is 714 is a composite number or not ?
- As we already know that, the number having factors 1 and the number itself is the prime number.
- And numbers having more than these two factors are the composite numbers.
- To check whether the number 714 is composite or not first we have to find its factors.
Contents
Factors of 714:
- If we have taken numbers from 1, 2, 3…for checking factors of 714, we found that 714 has factors 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714. Hence, we must say that 714 is a composite number.
- Thus, 714 is the composite umber.
- If we multiply 714 by 1, 2, 3 then we get the multiples of 714 which are 714, 1428 and so on.
About the number 714:
- 714 has more than two factors which are 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714 and hence it is the composite number.
- 714 is the even composite number and it is not the perfect square also.
- If we divide 714 by 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714 then we get remainder as zero. Hence, 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714 are the factors of 714.
Note:
- 714 is not the perfect square.
- Factors of 714: 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714
- Prime factors of 714: 2, 3, 7, 17
Conclusion:
- 714 is the composite number which has factors 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714
- And hence, 714 is not the prime number.
Multiple Choice Questions:
1) 714 is a
a) perfect square number
b) Even number
c) Composite number
d) Both b and c
Ans: d) both b and c
2) The composite factors of a composite number 714 are
a) 6, 14, 21, 34, 42, 51, 102, 119, 238, 357 ,714
b) 2, 3, 7, 17
c) 1, 6, 14, 21, 34, 42, 51, 102, 119, 238, 357 and 714
d) 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714
Ans: a) 6, 14, 21, 34, 42, 51, 102, 119, 238, 357 ,714
3) 714 is the composite number because
a) It has factors 1, 2, 3, 6, 7, 14, 17, 21, 34, 42, 51, 102, 119, 238, 357 and 714
b) More than two factors
c) Divisible by 2
d) Both a and b
Ans: d) both a and b