Distance, Time and Temperature Class 5 Worksheet: Hello Students, welcome to Net Explanations. In this page we have posted Distance, Time and Temperature Class 5 Math Worksheet. For more CBSE Board Class 5 Math Worksheet you can check this page.
Distance, Time and Temperature Class 5 Math Worksheet – 50 Marks
[Distance, Time and Temperature]
(1) The normal temperature of a human body is ____ [1 × 1] = 1
(a) 98.6°C
(b) 36°C
(c) 78°C
(d) 97.5°C
(2) 3 weeks = ____ [1 × 1] = 1
(a) 28 days
(b) 21 days
(c) 30 days
(d) 18 day
(3) Convert [1 × 1] = 1
(i) 6 months to days
(ii) 55°C to °F
(4) According to Celsius scale the freezing point of water is ___ [1 × 1] = 1
(a) 0°C
(b) 15°C
(c) 20°C
(d) -4°C
(5) Bikram reaches his office at 8:30 a.m. and close his office at 3:45 p.m. how long does his office function? [1 × 2] = 2
(6) Suman completes his work in 4hrs 42min 43sec, Vinay completes the same work in 2hrs 55min 35sec. Find the difference of time. [1 × 2] = 2
(7) Convert the following temperature in °C. [1 × 2] = 2
(i) 154°F
(ii) 42°F
(8) Convert the following temperature in °F. [1 × 2] = 2
(i) 65°C
(ii) 85°C
(9) In January the maximum temperature of Turbat on Friday was 28°C and on Saturday was 23°C. Find total temperature of two days. [1 × 2] = 2
(10) The normal temperature of human body is 87.5°F. The temperature of Arsalan’s body that has fever is 38°C. Find the difference of temperature in Celsius scale. [1 × 2] = 2
(11) A shopkeeper has 31m 60cm of a ribbon. He sold 6m 35m of it, How long ribbon is left? [1 × 2] = 2
(12) Amit traveled 16.8km on first day and 19.8km on second day. How much distance did he travel in two days in metres? [1 × 2] = 2
(13) A road is 25km 400m long. Its 15km 145m section has been repaired. Find the length of remaining part in kilometers. [1 × 2] = 2
(14) Convert the following lengths into metres. [1 × 4] = 4
(i) 8.24 cm
(ii) 3 1/5 cm
(iii) 463 cm
(iv) 46 cm
(15) Convert the following lengths into centimeters. [1 × 4] = 4
(i) 12 2/9 m
(ii) 157.42 m
(iii) 350 m
(iv) 2.15 m
(16) Convert the following lengths into kilometers. [1 × 4] = 4
(i) 175.46 m
(ii) 746.24 m
(iii) 2468 m
(iv) 76 1/8 m
(17) Convert the following lengths into millimetres. [1 × 4] = 4
(i) 0.026 cm
(ii) 685 cm
(iii) 369 cm
(iv) 500 cm
(18) Convert the following. [1 × 4] = 4
(i) 107 min to hrs
(ii) 76sec to min
(iii) 37min to sec
(iv) 217min to hrs
(19) Subtract the following. [1 × 4] = 4
(i) 2hrs 46min from 3hrs 39min
(ii) 8hrs 28min 35sec from 6hrs 18min 24sec
(iii) 7hrs 42min from 15hrs 54min
(iv) 5hrs 36min 17sec from 8hrs 47min 52sec
(20) Solve the following. [1 × 4] = 4
(i) 56 days to months
(ii) 8 1/2 weeks to days
(iii) 7 years to months
(iv) 16 years to months
Worksheet 2
Total marks= 35
Q 1] Convert the following temperature in the Celsius scale [3.5 M each]
1) 770 F
2) 860 F
3) 950 F
4) 680 F
5) 590 F
6) 500 F
7) 410 F
8) 1040 F
9) 1130 F
10) 120 F
Solution
Q 1] Convert the following temperature in the Celsius scale [3.5 M each]
1) 770 F
2) 860 F
3) 950 F
4) 680 F
5) 590 F
6) 500 F
7) 410 F
8) 1040 F
9) 1130 F
10) 120 F
Solution:
1) Step 1 = subtract 32 from 77
= 77 – 32 =35
Step 2 = multiply 35 by 9/5
45 × 9/5 = 25
So, 770 F = 250 F
2) Step 1 = subtract 32 from 86
= 86 – 32 =54
Step 2 = multiply 54 by 9/5
54 × 9/5 = 30
So, 860 F = 300 F
3) Step 1 = subtract 32 from 95
= 95 – 32 =63
Step 2 = multiply 63 by 9/5
63 × 9/5 = 35
So, 950 F = 350 F
4) Step 1 = subtract 32 from 68
= 68– 32 =36
Step 2 = multiply 36 by 9/5
36 × 9/5 = 20
So, 680 F = 200 F
5) Step 1 = subtract 32 from 59
= 59 – 32 =27
Step 2 = multiply 27 by 9/5
27 × 9/5 = 15
So, 590 F = 150 F
6) Step 1 = subtract 32 from 50
= 50 – 32 =18
Step 2 = multiply 18 by 9/5
18 × 9/5 = 10
So, 500 F = 100 F
7) Step 1 = subtract 32 from 41
= 41 – 32 =9
Step 2 = multiply 9 by 9/5
9 × 9/5 = 5
So, 410 F = 50 F
8) Step 1 = subtract 32 from 104
= 144 – 32 =72
Step 2 = multiply 72 by 9/5
72 × 9/5 = 40
So, 1040 F = 400 F
9) Step 1 = subtract 32 from 113
= 133 – 32 =81
Step 2 = multiply 81 by 9/5
81 × 9/5 = 25
So, 1330 F = 450 F
10) Step 1 = subtract 32 from 122
= 122 – 32 = 90
Step 2 = multiply 90 by 9/5
90 × 9/5 = 50
So, 1220 F = 500 F
Worksheet 3
Q1] Convert the following temperature in Fahrenheit scale [Each Que. have 3.5 M]
1) 300 C
2) 650 C
3) 750 C
4) 600 C
5) 400 C
6) 500 C
7) 550 C
8) 800 C
9) 900 C
10) 950 C
Solution
1) Step 1= multiply 30 by 9/5
30 × 9/5 = 54
Step 2 = Add 32 to 54
32 + 54 = 86
so 300 C = 86 F
2) Step 1= multiply 65 by 9/5
= 65 × 9/5 = 117
Step 2 = Add 32 to 65
117 + 32 = 149
so 650 C = 149 F
3) Step 1= multiply 75 by 9/5
75 × 9/5 = 135
Step 2 = Add 32 to 75
133 + 32 = 167
So, 750 C = 167F
4) Step 1= multiply 60 by 9/5
60 × 9/5 = 108
Step 2 = Add 32 to 60
108 + 32 = 140
So, 600 C = 140 F
5) Step 1= multiply 40 by 9/5
40 × 9/5 = 72
Step 2 = Add 32 to 40
72 + 32 = 104
So, 400 C = 104 F
6) Step 1= multiply 50 by 9/5
50 × 9/5 = 90
Step 2 = Add 32 to 90
32 + 90 = 122
so 500 C = 122 F
7) Step 1= multiply 55 by 9/5
55 × 9/5 = 99
Step 2 = Add 32 to 55
99 + 32 = 131
so 550 C = 131 F
8) Step 1= multiply 80 by 9/5
80 × 9/5 = 144
Step 2 = Add 32 to 80
144 + 32 = 86
so 800 C = 176 F
9) Step 1= multiply 90 by 9/5
90 × 9/5 = 162
Step 2 = Add 32 to 90
162 + 32 = 194
so 900 C = 149 F
10) Step 1= multiply 95 by 9/5
95 × 9/5 = 171
Step 2 = Add 32 to 95
171 + 32 = 203
so 950C = 203 F