**CG SCERT Chhattisgarh State Board Class 5 Math Chapter 18 Perimeter Exercises Questions and Answers.**

**Chapter 18**

**1.)The length of a playground is 200 metre and the breadth is 150 metre . If Raju wants to go around the boundary once, how many metres would he have to run?**

Ans: The length of a playground is 200 metre the breadth is 150 metre

Metres required to go around boundary = p 2( l +b )

= 2(200+150)

= 350 ×2

= 700 m

Ans: Raju required to run 700 m

**2.) A square garden has a side of 250 metres. To put a wire fencing around this, what is the length of wire required**

Ans: A square garden side is 250m

To put a wire fencing around this,

what is the length of wire required = 250 × 4

= 1000m

Ans: 1000m of length of wire required.

**3.) What is the length of lace which would be required to be put around a handkerchief, which is a square with a side of 15 cm each? If you wanted to make 5 such handkerchiefs what length of lace would you need?**

Ans: side of a square with 15cm

Perimeter of a square is = 4×15cm

= 60cm

In order to make 5 handkerchiefs

= 60cm ×15cm

= 300cm

Ans: 300cm lace is required to make 5 handkerchiefs.

**Write the perimeter of each rectangle**

**1.) Length = 25 metres, breadth = 20 metres**

Ans: P = 2( l +b )

=2(25+20)

= 90m

**2.) Length = 32 metres, breadth = 18 metres**

Ans: P = 2( l +b )

= 2(32+18)

= 100m

**Give the perimeter of the following triangles**

**1.) 6 cm, 8 cm, 10 cm**

Ans: Perimeter =( 6+8+10) cm

= 24cm

**2.) 15 cm, 18 cm, 20 cm**

Ans: Perimeter ( 15+18+20)

= 53cm

**3.) 12 cm, 12 cm, 12 cm**

Ans: Perimeter ( 12+12+12)cm

= 36cm

**Find the perimeter of the following squares**

**1.) Each side = 8 metres**

Ans: perimeter 4 × 8

=32m

**2.) Each side = 11 metres**

Ans: 11×4

= 44m

**3.) Each side = 35 metres**

Ans: 35×4

=140m