RS Aggarwal Class 8 Math Eighth Chapter Linear Equations Exercise 8A Solution
EXERCISE 8A
Solve:
(1) 8x + 3 = 27 + 2x
⇒ 8x – 2x = 27 – 3
⇒ 6x = 24
⇒ x = 4
(2) 5x + 7 = 2x – 8
⇒ 5x – 2x = – 8 – 7
⇒ 3x = – 15
⇒ x = – 5
(3) 2z – 1 = 14 – z
⇒ 2z + z = 14 + 1
⇒ 3x = 15
⇒ z = 5
(4) 9x + 5 = 4(x – 2) + 8
⇒ 9x + 5 = 4x – 8 + 8
⇒ 9x – 4x = – 5
⇒ 5x = – 5
⇒ x = -1
⇒ 7y = 5y – 20
⇒ 7y – 5y = – 20
⇒ 2y = – 20
⇒ y = – 10
(7) 15(y – 4) – 2(y – 9) + 5(y + 6) = 0
⇒ 15y – 60 – 2y + 18 + 5y + 30 = 0
⇒ 18y – 60 + 48 = 0
⇒ 18y – 12 = 0
⇒ 18y = 12
(8) 3(5x – 7) – 2(9x – 11) = 4(8x – 13) – 17
⇒ 15x – 21 – 18x + 22 = 32x – 52 – 17
⇒ – 3x + 1 = 32x – 69
⇒ – 3x – 32x = – 69 – 1
⇒ – 35x = – 70
⇒ x = 2
⇒ t – 18 = 8 – 12t
⇒ t + 12t = 8 + 18
⇒ 13t = 26
⇒ t = 2
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