Exercise 12.2
1. Find:
(i) 22% of 120
Solution:
(ii) 25% of Rs 1000
Solution:
(iii) 25% 0f 10 kg
Solution:
(iv) 16.5% of 5000 metre
Solution:
(v) 135% of 80 cm
Solution:
(vi) 2.5% OF 10000 ml
Solution:
Go beyond traditional BBA College with NEXIS 3-year UG
2. Find the number a, if
(i) 8.4% of a is 42
Solution:
(ii) 0.5% of a is 3
Solution:
(iii) of a is 50
Solution:
(iv) 100% of a is 100
Solution:
3. x is 5% of y, y is 24% of z. if x = 480, find the values of y and z.
Solution:
Given,
= x is 5% of y
= x= (5/100) y
= y = (100/5) x
= y = 20 x
= y = 20(480)
= y = 9600
Also given,
= y is 24% of z
= y= 24/100 z
= z= 100/24 y
= z = (100/24) × 9600
= z = 40000
4. A coolie deposits Rs.150 per month in his post office savings bank account. If this is 15% of this monthly income, find his monthly income.
Solution:
Let the monthly income coolie be “a”
ie, the equation becomes
= 15% of a = 150
a = 1000
Therefore, the monthly income of a coolie is Rs. 1000
5. Asha got 86.875 % marks in the annual examination. If she got 695 marks, find the total number of marks of the examination.
Solution:
Let the total number of marks in the examination be “a”
From the given data, the equation can be written as
86.875% of a = 695
Therefore, the total number marks in the examination is 800
6. Deepti went to school for 216 days in a full year. If her attendance is 90%, find her number of days on which the school was opened?
Solution:
Let the school was opened for x days
According to the question,
= 90 % of x = 216
The school was opened for 240 days in the given year.
7. A garden has 2000 trees. 12% of these are mango trees, 18% are lemon and the rest are orange trees. Find the number of orange trees?
Solution:
Let the number of orange trees be x
There are total 2000 trees.
According to the question,
12% of total trees are mango
Number of mango trees = 12% of 2000
= 360
Number of orange tress = (2000-240-360)
= 140
Number of orange trees are 1400.
8. Balanced diet should contain 12% of proteins, 25% of fats and 63% of carbohydrates. If a child needs 2600 calories in this food daily, find in calories the amount of each of these in his daily food intake?
Solution:
In a balanced diet of 2600 calories
12 % protein. Amount of protein intake = 12% of 2600 = (12/100) × 2600 = 312 calories
25 % fats. Amount of fats intake = 25% of 2600 = (25/100) × 2600 = 650 calorie
Amount of carbohydrates intake = 2600 – (315 + 650) = 1638 calories
9. A cricketer diet scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What is the percentage of total runs came in:
Solution:
1) Sixes
The cricket hits 3 sixes = 3(6) = 18
2) Fours
The cricket hints 8 four = 8(4) = 32
3) Twos
The cricket hints 2 twos = 2(2) = 4
4) Singles
The Cricketer hints 8 singles = 8(1) = 8
10. A cricketer hits 120 runs in 150 balls during a test match. 20% of the runs came in 6’s. 30% in 4’s. 25% in 2’s. And rest in 1’s. How many rubs did he score in?
Solution:
Let us assume the cricketer scored w runs in 6’s.
20% of 120 = w
= w = 24
Let us assume the cricketer scored x runs in 4’s.
30% of 120 = x
= x = 36
Let us assume the cricketer scored w runs in 2’s.
25% of 120 = y
= y = 30
Let us assume the cricketer scored z runs in 1’s.
24 + 36 + 30 + z = 120
= z = 30
The cricketer scored 30 runs by taking singles.
11. Radha earns 22% of her investment. If she earns Rs. 187, then how much did she invest?
Solution:
Let the investment be Rs. x
According to the question
22% of x = 187
= x = 850
Radha invested Rs. 850
12. Rohit deposits 12% of his income in a bank. He deposited Rs. 1440 in the bank during 1997. What was his total income for the year 1997?
Solution:
Let the total income of Rohit for a year, 1997 be Rs .a
From the given information, we can write it as
12% of x =1440
a = 12000
Therefore, the total income of Rohit during 1997 is Rs.12, 000.
13. Gun powder contains 75% nitre and 10% sulphur. Find the amount of gun powder which carries 9 kg of nitre. What amount of gun powder would contain 2.3 kg of sulphur?
Solution:
Assume that the amount of gun powder that contains 9 kg nitre be “a” kg
From the given information, we can write it as
a = 12kg
Therefore, the amount of gun powder that carries 9 kg nitre is 12 kg
Also, assume that the amount of gun powder that contains 2.3 kg sulphur be “b” kg
Therefore, the amount of gun powder that carries 2.3 kg sulphur is 23 kg.
14. An alloy of tin and copper consists of 15 parts of tin and 105 parts of copper. Find the percentage of copper in the alloy?
Solution:
Composition of the alloy = 15 parts if tin + 105 parts of copper
Therefore, percentage of tin = Let the amount of gun powder that contains 9 kg nitre be x kg
= y = 87.5%
The percentage of copper is 87.5%
15. An alloy contains 32% of copper, 40% of nickel and rest zinc. Find the mass of the zinc in 1 kg of alloy?
Solution:
Percentage of copper in the alloy = 32%
Percentage of nickel in the alloy = 40%
Percentage of zinc in the alloy = 100 – (32 + 40) = 28%
Amount of zinc in 1 kg of alloy = 0.28(1) = 280 gm
The mass of zinc in 1 kg of the alloy is 280 gm.
16. A motorist travelled 122 kilometres before his first stop. If he had 10% of his journey to complete at this point, how long was the total ride?
Solution:
Let the length of the total ride be x km
According to the question
10% of x = 122
= x = 1220 km
The total length of the total ride is 1220 km.
17. A certain school has 30 students, 142 of whom are boys. It has 30 teachers, 12 of which are men. What percent of total number of students and teachers in the school is female?
Solution:
Total number of female students = 300 – 142 = 158
Number of female teachers = 30 – 12 = 18
Total number of females = 158 + 18 = 176
Total population of the school = 300 + 30 = 330
Percentage of teacher in the school is female is = (176/330) × 100
= 53.33%
The percentage of total number of students and teachers in the school is female is 53.33%
18. Aman’s income is 20% less than that of anil. How much present is anil’s income more than aman’s?
Solution:
Let anil’s income be x
Then, aman’s income = (x − 20)100 = 8 × 10
Difference in the incomes of anil and aman to that of aman’s income
=25%
Anil’s income is 25% more than that of aman’s.
19. The value of the machine depreciates every year by 5%. If the present value of the machine is Rs.100000, what will be it’s value after 2 years?
Solution:
It is given that the value of the machine depreciates by 5% every year. Present value of the machine = Rs.100000
Therefore, 5% of 100000 = Rs.5000
Value of the machine after 1st year = Rs (100000 – 5000)
= Rs. 95000
5 % of 95000 = Rs.4750
Value of the machine in the 2nd year =Rs (95000 – 4750)
= Rs 90250
After two years, the value of the machine will be Rs.90250
20. The population of the town increased by 10% annually. If the present population is 60000, what will be its population after 2 years?
Solution:
Present population = 60000
It increases 10% annually
Increase in the population in the first year = 60000 + 6000 = 66000
66000 is the increase in the population in the second year = 10% of 66000 = 6600
Thus population after 2 years = 66000 + 6600 = 72600
The population of the town after 2 years is 72600.
21. The population of the town is increased by 10% annually. If the present population is 22000, find the population a year ago.
Solution:
Let the population of the town before 1 year be “a”
It is given that the population of the town increases by 10%
So, the present population of the town = a+10% of a
Given that, the present population of the town = 22000
From the given information, we can write it as,
Hence, the population of the town before a year is 20000.
22. Ankit was given an increment of 10% on his salary. His new salary is Rs. 3575. what was his salary before investment?
Solution:
Let the initial salary of Ankit be Rs. a
From the given data, we can say that
New salary of Ankit = Before increment + increment given on salary
= a+ 10% of a = 3575
=3250
Therefore, the salary of Ankit before increment is Rs.3250
23. In a new budget, the price of petrol rose by 10%. By how much per cent must one reduce the consumption so that the expenditure does not increase?
Solution:
Assume that the consumption of petrol be 100 litres and the price is Rs.100, then
So the new price of petrol is Rs 110, because of the price of petrol increases by 10%.
Therefore, now Rs 110 can fetch 100 litres of petrol.
So, Rs 100 can fetch = (100/110)x 100
= 10000/110
=1000/11 litres of petrol.
Therefore, the reduction in the consumption of petrol = (100- (1000/11))%
= 100/11 %
Therefore, the percentage reduction in consumption =9(1/11)%
24. Mohan’s income is Rs.15500 per month. He saves 11% of his income. If his income is increased by 10%, then he reduces his saving by 1%, how much does he save now?
Solution:
Mohan’s saving = 11% of 15500
Thus, the amounts of his present and earlier saving are the same
25. Shikha’s income is 60% more than that of shalu. What percent is shalu’s income less than shikha’s?
Solution:
Let shalu’s income be Rs.x
Shikha’s income = Rs x + 60% of x
Percentage of the difference in the incomes of shikha and shalu to that of shikha’s income = 37.5%
26. Rs.3500 is to be shared among three people so that the first person gets 50% of the second, who in turn gets 50% of the third. How much will each other of them get?
Solution:
Let a, b, and c be the amounts received by the first, second, third person respectively.
Given that
a= 50% of b
b = 2a
Again, b = 50% of c
b = 1/ 2 c
c= 2b
Therefore, c=2b=4a
= a+b+c= 3500
Substituting the value of z and y we get,
= a+2b+4c = 3500
= 7a = 3500
= a= 500
= b=2a = 2(500) = 1000
=c= 4a = 4(500) = 2000
Therefore, the amount received by three persons are 500, 1000 and 2000 respectively.
27. After a 20% hike, the cost of Chinese vase is Rs2000. What was the original price of the object?
Solution:
Let the original price of the object be Rs. X
According to the question,
We have 20% of x+x = 2000
= x = 1666.67
The original price of the object is Rs. 1666.67 .
