Mole Concept and Stoichiometry Class 10 ICSE Chemistry MCQ Questions
Looking for Mole Concept and Stoichiometry Class 10 ICSE Chemistry Chapter 5 MCQ Questions? If yes, You are the right page. Here we have provided ICSE class 10 chemistry Chapter 5 multiple choice questions and answers. All MCQ are important.
1) Calculate the molecular mass of methane.
a) 12
b) 14
c) 18
d) 16
Answer – 16
2) What is Avagadro’s number ?
a) 6.021×10^21
b) 6.022×10^22
c) 6.022×10^23
d) 6.021×10^21
Answer- 6.022×10^23
3) The number of atoms in a molecule of an element is called
a) Atomic number
b) Mass number
c) Atomicity
d) Moelcular mass number
Answer – Atomicity
4) What is the empirical formula of C2H6?
a) C2H3
b) CH4
c) CH2
d) CH3
Answer- CH3
5) What is the pressure volume relationship when temperature is constant?
a) PV=nRT
b) P2=P1V1
c) P1V1= P2V2
d) Non of the above
Answer – P1V1=P2V2
6) During formation of ammonia the ratio is___
a) 1:2:1
b) 1:3:2:1
c) 2:3:1
d) 1:3:2
Answer- 1:3:2
7) The relative molecular mass of a gas or vapour is ___ it’s vapour density.
a) once
b) twice
c) thrice
d) four Times
Answer- twice
8) Standard value of temperature is considered as
a) 253K
b) 263
c)273K
d) 283k
Answer- 273K
9) What is the correct empirical formula for acetic acid?
a) CH2O
b) C2H2O
c) CHO
d) CH2O2
Answer- CH2O
10) Ratio of formation of carbon dioxide is
a) 1:2:1
b) 2:2:1
c) 3:2:1
d) 2:1:2
Answer- 2:1:2
11) How many volumes of Chlorine is required to form 2volumes of Hydrogen chloride?
a) 1
b)2
c) 3
d) 4
Answer- 1 vol
12) If the empirical formula is C2H8 and the value of n is 2 then molecular formula will be___
a) C4H8
b) C6H10
c) C4H16
d) C4H18
Answer- C4H16
13) Atomic mass of a unit atom is defined as __
a) 1/16th of atomic mass of oxygen
b) 1/12th of atomic mass of oxygen
c) 1/16th of atomic mass of C-12
d) 1/12th of atomic mass of C-12
Answer- 1/12th of atomic mass of C-12
14) Avagadro’s number is denoted by
a) NA
b)NB
c) NC
d) ND
Answer- NA
15) Formula for number of molecules is
a) Atomic mass/ 6.022×10^23
b) Atomic number/ 6.022×10^23
c) Atomic mass/ 6.021×10^23
d) Atomic number/6.021×10^23
Answer- Atomic mass/ 6.022×10^23
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