Is 4902 is a composite number or not ?
- As we already know that, the number having factors 1 and the number itself is the prime number.
- And numbers having more than these two factors are the composite numbers.
- To check whether the number 4902 is composite or not first we have to find its factors.
Contents
Factors of 4902:
- If we have taken numbers from 1, 2, 3…for checking factors of 4902 we found that 4902 has factors 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902. Hence, we must say that 4902 is a composite number.
- Thus, 4902 is the composite number.
- If we multiply 4902 by 1, 2, 3 then we get the multiples of 4902 which are 4902, 9804 and so on.
About the number 4902:
- 4902 has more than two factors which are 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902 and hence it is the composite number.
- 4902 is the even composite number and it is not the perfect square also.
- If we divide 4902 by, 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902 then we get remainder as zero. Hence, 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902 are the factors of 4902.
Note:
- 4902 is not the perfect square.
- Factors of 4902: 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902
- Prime factors of 4902: 2, 3, 19, 43
Conclusion:
- 4902 is the composite number which has factors, 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902
- And hence, 4902 is not the prime number.
Multiple Choice Questions:
1) 4902 is a
a) Prime number
b) even number
c) even Composite number
d) Both a and c
Ans: c) even composite number
2) The prime factors of a composite number 4902 are
a) 4902
b) 2, 3, 19, 43
c) 6, 38, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902
d) 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902
Ans: b) 2, 3, 19, 43
3) 4902 is even composite number because
a) It has factors 1, 2, 3, 6, 19, 38, 43, 57, 86, 114, 129, 258, 817, 1634, 2451 and 4902
b) It has more than two factors
c) Divisible by 2
d) all
Ans: d) all