Is 2568 is a composite number or not ?
- As we already know that, the number having factors 1 and the number itself is the prime number.
- And numbers having more than these two factors are the composite numbers.
- To check whether the number 2568 is composite or not first we have to find its factors.
Contents
Factors of 2568:
- If we have taken numbers from 1, 2, 3…for checking factors of 2568, we found that 2568 has factors 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568. Hence, we must say that 2568 is a composite number.
- Thus, 2568 is the composite number.
- If we multiply 2568 by 1, 2, 3 then we get the multiples of 2568 which are 2568, 5136 and so on.
About the number 2568:
- 2568 has more than two factors which are 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568 and hence it is the composite number.
- 2568 is the even composite number and it is not the perfect square also.
- If we divide 2568 by, 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568 then we get remainder as zero. Hence, 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568 are the factors of 2568.
Note:
- 2568 is not the perfect square.
- Factors of 2568: 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568
- Prime factors of 2568: 2, 3, 107
Conclusion:
- 2568 is the composite number which has factors, 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568
- And hence, 2568 is not the prime number.
Multiple Choice Questions:
1) 2568 is a
a) Even number
b) Odd number
c) Composite number
d) Both a and c
Ans: d) both a and d
2) The prime factors of a composite number 2568 are
a) 2568
b) 2, 3, 107
c) 1, 4, 6, 8, 12, 24, 214, 321, 428, 642, 856, 1284 and 2568
d) 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568
Ans: b) 2, 3, 107
3) 2568 is composite number because
a) It has factors 1, 2, 3, 4, 6, 8, 12, 24, 107, 214, 321, 428, 642, 856, 1284 and 2568
b) It has more than two factors
c) Divisible by 2
d) Both a and b
Ans: d) both a and b