Chapter 6.3 Solution West Bengal Board : Class 7 Mathematics
West Bengal Board Class 7 Math Solution full Exercise 6.3 by Experts. Here in this page WB Board Class 7 Student can find Ganit Prabha Class 7 Math Chapter 6 বীজগাণিতিক প্ৰক্ৰিয়া (Algebraic Process) Exercise 6.3 Solution.
Board | WB Board |
Class | 7 (Seven) |
Subject | Mathematics |
Book Name | Ganit Prabha |
Chapter | 6 |
Chapter Page Number on Book | 108 and 109 |
Exercise Number | 6.3 |
(1)
(i) 3a x 4b = 12ab
(ii) 12ab ÷ 3a = 4b
(iii) 12ab ÷ 3 = 4ab
(iv) (-x2) x X = -x3
(v) 9x2 ÷ 3x2 = 3
(vi) x2 x x2 = x4
(vii) x2 x 1/ x2 = 1
(viii) 0 ÷ ab = 0
(ix) 4a2b2c2 x 0 = 0
(x) 3ab ÷ 3b = a
(xi) x0 x y = y
(xii) x ÷ 0 = no value
(2)
(a) 2x2 x (-3y) x 6z
= -6x2y x 6z
= – 36 x2yz
(b) 7xy2 x 8 x2y x Xy
= 56x3y3 x Xy
= 56 x4y4
(c) (-3a2) x (4a2b) x (-2)
= -12a3b x (-2)
= 24 a3b
(d) (-2mn) x 1/6 m2n2 x 13m4n4
= -1/3 m3n3 x 13m4n4
= -13/3 m7n7
(e) 2/3 x2y x 3/5xy2
= 2/5 x3y3
(f) -18/5 x2z) x (25/6 xz2y)
= – (18/5 x 25/6) x3yz3
= -15 x3yz3
(g) (-3/5 s2t) x (15/7 st2u) x (7/9 su2)
= (-3/5 x 15/7 x 7/9) s4t3u3
= – 3s4t3u3
(h) (4/3 x2yz) x (1/3 y2zx) x (-6xyz2)
= (4/3 x 1/3 x -6) x4y4z4
= -8/3 x4y4z4
(i) 4a (3a+7b)
= 12a2 + 28ab
(j) 8a2 x (2a + 5b)
= 16 a3 + 40 a2b
(k) -17 x2 x (3x-4)
= -51x3 + 68 x2
(l)2/3abc (a2 +b2 -3c2)
= 2/3 a3bc + 2/3b3ac – 2/a abc3
(m) 2 x 5x (10x2y-100xy2)
= 100x3y – 1000 x2 y2
(n) (2x+3y) (5x-y)
= 10x2 – 2xy +15xy – 3 y2
= 10x2+13xy – 3y2
(o) (a2-b2) (2b-6a)
= 2 a2b – 6a3 – 2b3 + 6ab2
(p) (x+2) (3x+1)
= 3x2 + x + 6x + 2
= 3x2 + 7x + 2