West Bengal Board Class 7 Math Chapter 6.2 Solution

Chapter 6.2 Solution West Bengal Board : Class 7 Mathematics

West Bengal Board Class 7 Math Solution full Exercise 6.2 by Experts. Here in this page WB Board Class 7 Student can find Ganit Prabha Class 7 Math Chapter 6 বীজগাণিতিক প্ৰক্ৰিয়া (Algebraic Process) Exercise 6.2 Solution.

Board WB Board
Class 7 (Seven)
Subject Mathematics
Book Name Ganit Prabha
Chapter 6
Chapter Page Number on Book 94 and 95
Exercise Number 6.2

(1)

(i) 5x+3x

= 8x

(ii) 9y -3y

= 6y

(iii) -4y + 7y

= 3y

(iv) -10 x – 2x

= -12x

(v) 3a + 4a -2a

= 5a

(vi) -7x – 2x +5x

= – 4x

(vii) 6p -2p + 3p

= 7p

(viii) 4x2 – 2x2 -3x2 + x2

= 2x2 – 3x2 + x2

= 0

(ix) 5a2b – 2a2b – 3a2b + 8a2b

= 3a2b– 3a2b + 8a2b

=  8a2b

(x) 3x2 – 6x2 – 2x2 – x2 + 6x2

= – 3x2 – 3x2+ 6x2

=- 6x2+ 6x2

= 0

(3)

(i) 3a + b; 2a + 4b; 5a – b

= 3a + b + 21a 4b + 5a – b

= 10a + 4b

(ii) 5a – 4 + 2a + 3 + 2a – 3

= 9a – 4 + 3 – 3

= 9a – 4

(iii) 6a2 +7a +3 + 9a2 – 2a + 7 + 4a2-2a + 9

= 19a2 + 3a + 19

(iv) 2a2b + 5b2a + 7 + 3a2b – 2b2a + 6 + 8a2b – b2a + 9

= 13 a2b + 2b2a + 22

(v) 4xy + 5x + 7y – 4xy – y – 3x + 3xy – 3y + 2x

= 3xy + 3y

(4)

(i) (8x +6y) – (2x +3y)

= 8x + 6y – 2x – 3y

= 6x + 3y

(ii) ( -3m2 + 2m+ 2) – ( m2 – 2)

= -3m2 + 2m+ 2 – m2 – 2

= -4m+ 2m + 4

(iii) (2x + 3y) – (8x + 4y + 7)

=  2x + 3y – 8x – 4y – 7

= – 6x – y – 7

(iv) (-9a2 + 3a + 2) – (5a2+ 2a – 1)

= -9a2 + 3a + 2 – 5a2+ 2a – 1

= -14a2 + a + 3

(v) x – (-2x2 + 3y2)

= x + 2x2 + 3y2

(vi) (3x2 + 5xy) – (2x + xy + 3y2)

= 3x2 + 5xy – 2x + xy + 3y2

= x2 + 4xy – 3y2

(5)

(a) 17x2y – 3xy2 + 14x2y + 2xy2

= 31x2y – xy2

(b) -5b + 18a + 6b – 2a

= b + 16a

(c) 4m2 + 3n2 – (6m2 + 7n2)

=  4m2 + 3n2 –6m2 + 7n2

= -2 m2 – 4n2

(d) a- b – (a-b)

= a – b – b + a

= 2a – 2b

(e) (6p – 4q+2r) + (2p + 3q – 4r)

= 6p – 4q + 2r + 2p + 3q – 4r

= 8p – q – 2r

(f) –x +y + z – 2x + 3y – 2

= – 3x + 4y

(g) (x2 + 2x -5) + (3x2 – 8x + 5)

= x2 + 2x -5 + 3x2 – 8x + 5

= 4x2 – 6x

(h) (7x2 – 3x + 3) – (2x2 – 13x – 7)

= 7x2 – 3x + 3 – 2x2 – 13x – 7

= 5x+ 10x + 10

(i) 6a – 2b – ab – (3a + b –ab) + 2ab – b + a

= 6a – 2b – ab – 3a + b –ab + 2ab – b + a

= 4a – 4b + 2ab

(9) (-11x -7y -9z) – (-7x+3y-5z)

= -11x -7y – 9z + 7x – 3y + 5z

= – 4x – 10y – 4z

(10) (3×2+4x) + (5x2-x)

= 3x2 + 4x + 5x2 – x

= 8x2 + 3x

 (8x2 + 3x) – (3x – 5x2)

= 8x2 + 3x – 3x + 5x2

= 13x

(11) (5 + 9x) + (6 – 7x + 4x2)

= 5 + 9x + 6- 7x + 4x2

= 4x2 + 2x + 11

 (x2 – 9x) + (2x2 + 3x + 5)

= x2 – 9x + 2x2 + 3x + 5

= – x2 – 6x + 5

(4x2 + 2x + 11) – (- x2 – 6x + 5)

= 4x2 + 2x + 11+ x2 + 6x – 5

= 5 x2 + 8x + 6

Updated: August 7, 2020 — 11:52 pm

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