**Telangana SCERT Solution Class IX (9) Math Chapter 9 Statistics Exercise 9.2**

**(7)** From the given distribution table

Mean saving in Mondal Amberpet = 2154/6 ((Total saving)/(no of schools))

= 359

Mean saving in Mandal Thirumalgiri = 2478/6

= 413

Mean saving in Mandal Saidabad = 975/5

= 195

Mean saving in Mandal Khairathabad = 912/4

= 228

Mean saving in Mandal Secundarabad = 600/3

= 200

Mean saving in Mandal Bahadarpura = 7533/9

= 837

Arithmetic mean of saving of all school

= (sum of savings of all school)/(Total No of schools)

= (2154+2478+975+912+600+7533)/(6+6+5+4+3+9)

= 14652/33

= 444

∴ Men saving per school = 444

**(9)** Given,

Mean weight of 3 students = 40 kg

Ranga weighs 46 kgs

Rahim & Reshma weigh the same

Let, Rehim’s and Reshmas weight be x

Mean = (sum of weights of 3 students)/(Total no of students)

Or, 40 = (46+x+x)/3

Or, 2x + 46 = 120

Or, x = (120-46)/2

= 74/2

= 37 kgs

Rahim’s weight is 37 kgs.

It is very useful for the answers

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