Telangana SCERT Class 9 Math Solution Chapter 4 Lines and Angles Exercise 4.2

Telangana SCERT Solution Class IX (9) Math Chapter 4 Lines and Angles Exercise 4.2

(1)

Given,

x : y : z = 2 : 3 : 5

Let,

x = 2a

y = 3a

z = 5a

The angle of the full circle is 360o

Here,

AOE = xo [Vertically opposite angles]

∠ BOD = zo [Vertically opposite angles]

∠ COF = yo [Vertically opposite angles]

∠AOE + ∠EOD + ∠BOD + ∠BOF + ∠COF + ∠AOC = 360O

Or, x + y + z + x + y + z = 360o

Or, 2x + 2y + 2z = 360o

Or, 2(2a) + 2(3a) + 2(5a) = 360o [putting the values of x,y,z]

Or, 4a + 6a + 10a = 360o

Or, 20a = 360o

Or, a = 360o/20

= 18o

X = 2 x a

= 2 x 18o

= 36o

Y = 3a

= 3 x 18o

= 54o

Z = 5a

= 5 x 18o

= 90o

Hope above 4.2 Exercise Solution will help you to complete each math problem in a better way.


Updated: September 18, 2021 — 4:48 pm

1 Comment

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  1. In 2nd question (iii) bit, you given wrong answer. The correct answer is 20

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