Telanagana SCERT Solution Class VII (7) Math Chapter 2 Fractions, Decimals and Rational Numbers .
Exercise 1 Solution
Exercise 2
(5) (i) 55.5 = 50 + 5 + 5/10
(ii) 5.55 = 5 + 5/10 + 5/100
(iii) 303.03 = 300 + 3 + 3/100
(iv) 30.303 = 30 + 3/10 + 3/100
(v) 1234.56 = 1000 + 200 + 30 + 4 + 5/10 + 6/100
(6) (i) 3.46 = 3
(ii) 32.46 = 30
(iii) 7.43 = 3/100
(iv) 90.30 = 3/10
(v) 794.037 = 3/100
(7) Aruna travelled total path = AB + BC
=(9.50 + 2.40) Km
= 11.90 km
Radha travelled total path = ED + DC
= (8.25 + 3.75) km
= 12.00 km
Hence, Radha travelled more path by (12 – 11.90) km
= 0.10 km
(8) Upendra carry total weight back to his house,
2 kg 250 gm + 2 kg 500 gm + 75 gm + 125 gm
= 5 kg 525 gm
Therefore, Upendra carry 5 kg 525 gm weight to his house.
Exercise 6
(1) (i) 0.3 x 6 = 1.8
(ii) 2,7 x 7 = 18.9
(iii) 2.71 x 5 = 13.55
(iv) 19.7 x 4 = 78.8
(v) 0.05 x 7 = 0.35
(vi) 210.01 x 5 – 1050.05
(vii) 0.86 x 2 = 1.72
(2) Area of rectangle, 6.2 cm x 4 cm
= 24.8 cm square
6,2 x 4 = 24.8
(3)
(I) 21.3 X 10
= 213
(ii) 36.8 x 10
= 368
(iii) 53.7 x 10
= 537
(iv) 108.07 x 10
= 168.7
(v) 131.1 x 10
= 1310
(vi) 156.1 x 100
= 15610
(vii) 3.62 x 100
= 362
(viii) 43.07 x 100
= 4307
(ix) 0.5 x 10
= 5
(x) 0.08 x 10
= 0.38
(xi) 0.9 x 100
= 90
(xii) 0.03 x 1000
= 30
(4) In 1 lit petrol the bike correct 62.5 km
In 10 lit petrol the bike correct 62.5 x 10 km
= 625 km
(5) (i) 1.5 x 0.3 = 0.45
(ii) 0.1 x 47.5 = 04.75
(iii) 210.8 x 0.2 = 042.16
(iv) 4.3 x 3.4 = 14.62
(v) 0.05 x 0.5 = 0.025
(vi) 11.2 x 0.10 = 01.120
(vii) 0.02 x 1.07 = 1.0214
(viii) 10.05 x 1.05 = 10.5525
(ix) 101.01 x 0.01 = 001.0101
(x) 70.01 x 1.1 = 77.011
(6) (i) 2.3/1000 = 23/100×10 = 0.023
(ii) 0.45/5 = 45/100×5 = 0.09
(iii) 44.3/10 = 443/10×10 = 4.43
(iv) 127.1/1000 = 1271/1000×10 = 0.1271
(v) 7/3.5 = 7×10/35 = 2
(4) (i) False
(ii) True
(iii) False
(iv) False
(v) True