Telangana SCERT Class 10 Physical Science Chapter 6 Solution – Structure of Atom. Here in this post we provides Class 10 Physical Science Structure of Atom Telangana State Board Solution. Telangana State Board English Class X Medium Students can download this Solution to Solve out Improve Your Learning Questions and Answers.
Telangana State Board Class 10 Physical Science Chapter 6 Structure of Atom Solution:
CHAPTER: – 6
Structure of Atom
Exercise: –
Reflections of concepts –
1) What information does the electronic configuration of an atom provide?
Ans: – The electronic configuration of the atom tells us the characteristics of that atom as well as its position in periodic table. The various states like oxidation, reduction nature of that atom is known from it.
2) Rainbow is an example for continuous spectrum – explain.
Ans: – There is similarities between the continuous and spectrum and the Rainbow as all have the same types of phenomena like this two has no boundaries limit. And Rainbow is the formation of different spectrum and the continuous spectrum has also different wavelength.
3) How orbital is different from Bohr’s orbit?
Ans: – The orbital and the Bohr’s orbit are different as a orbit is nothing but the circular path of any planet whereas the Bohr’s orbit us the elliptical path around an atomic nucleolus.
4) Explain the significance of three Quantum numbers in predicting the positions of an electron in an atom.
Ans: – There are three quantum number of electron in an atom by which the difference characteristics of an atom are described like the principal quantum number tells us the energy levels of that atom, azimuth quantum number tells us the no of sub shell in that atom, spin quantum number tells us the magnetic states.
5) How we are using the nl^x method in writing electronic configuration?
Ans: – The n represents the no of principal quantum number; l represents the number of subshell and x represents no of electron present in that subshell. All of this clearly depicted the structure of that atom.
6) Which electronic shell is a higher energy level K or L?
Ans: – The electronic shell which is closer to the nucleus always has law energy level. So, L will have more energy level as compared to K.
Application of concepts
1) Answer the following questions.
a) How many maximum numbers of electrons can be accommodated in a principal energy level?
Ans: – The maximum number of electrons of an atom will be determined by the formula 2n^2 where n is the number of shells.
b) How many maximum numbers of electrons can be accommodated in a sub shell?
Ans: – The maximum number of electrons prese in a subshell is 2(2l + 1) where l is the number of subshells.
c) How many maximum numbers of electrons can be accommodated in an orbital?
Ans: – The maximum number of electrons that can be present in an orbital will be 2.
d) How many sub shells are present in a principal energy level?
Ans: – The no of subshell in an atom always equal to the no of principal quantum number of that atom.
e) How many spin orientations are possible for an electron in an orbital?
Ans: – The total number of spin orientation that possible for an orbital is 2.
2.) In an atom the number electrons in M-shell are equal to the number of electrons in the K and L Shell
Answer the following questions.
a.) Which is the outer most shell?
b.) How many electrons are there in its outermost shell?
c.) What is the atomic number of elements?
d.) Write the electronic configuration of the element.
Ans: – (a) The outer most shell is M.
(b) There are 20 electrons in an outer most shell.
(c) The atomic number of that element is 20.
(d) The electronic configuration of that elements is 1s^22s^22p^63s^23p^64s^2.
3.) Following orbital diagram shows the electron configuration of nitrogen atom. Which rule does not support this? N (Z = 7)
Ans: – The orbital diagram doesn’t show the principal of Hunds quantum number principal.
4.) Write the four quantum numbers for the differentiating electron of sodium (Na) atom?
Ans: – Na- 1s^22s^22p^63s^1. So, the four-quantum number are n=3; l=0; m=0; s=+1/2, -1/2;
5.) (i) An electron in an atom has the following set of four quantum numbers to which orbital does it belong.
Ans: – The quantum number which is it belongs is beryllium.
(ii) Write the four quantum numbers for 1s1 electron.
Ans: – Here, n=1;
L=1;
.m=-1, 0, 1;
S= +1/2, -1/2.
6.) The wave length of a radio wave is 1.0m. Find its frequency.
Ans: – The required formula is, v=cy
Here, frequency= v=? y=wavelength=1; c=3×10^8;
So, v= 3×10^8 Hz.
MULTIPLE CHOICE QUESTIONS
1) An emission spectrum consists of bright spectral lines on a dark back ground. Which one of the following does not correspond to the bright spectral lines?
A) Frequency of emitted radiation.
B) Wave length of emitted radiation.
C) Energy of emitted radiations.
D) Velocity of light.
Ans: – option (D).
2) The maximum number of electrons that can be accommodated in the L – shell of an atom is
A) 2 B) 4 C) 8 D) 16.
Ans: – Option (c).
3) If l = 1 for an atom then the number of orbitals in its sub-shell is
A) 1 B) 2 C) 3 D) 0.
Ans: – option (c) 3.
4) The quantum number which explains about size and energy of the orbit or shell is:
A) n B) l C) ml D) ms.
Ans: – Option (A) n.
More Important Questions
Q.1) MCQ.
1) Which of the following originated quantum theory?
a) David Bohr
b) Ludwig Planck
c) Rutherford
d) Dobereiner
2) The maximum number of electrons that can be accommodate in M-shell is….?
a) 8
b) 10
c) 18
d) 32
3) Principal quantum number represented by…………?
a) k
b) l
c) m
d) n
4) Spectrum is a group of……………?
a) Frequency
b) Velocity
c) Wavelength
d) Speed
5) If l=2 for an atom, then number of orbitals in its sub-shell is……?
a) 2
b) 3
c) 4
d) 5
6) If l=0, then number of atoms in its sub-shell is………?
a) 1
b) 2
c) 3
d) 0
Q.2) VERY SHORT ANSWER QUESTIONS
1) What is Hund’s rule?
2) Give Aufbau principal?
3) Give electronic configuration of N & O?
4) Give Pauli exclusion principal?
5) What is electronic configuration?
6) What is the shape of orbital?
Q.3) SHORT ANSWER QUESTIONS.
1) Complete the table?
(l)
Cingular momentum quantum no. |
Subshell | Number of
Degenerated Orbitals |
0 | ||
1 | ||
2 | ||
3 |
2) What is Electromagnetic Spectrum?
3) Which rule does not support in following diagram & draw diagram.
Q.4) LONG ANSWER QUESTIONS.
1) Answer the following questions.
a) Maximum number of electrons in principal energy level.
b) maximum numbers of electrons in on orbital.
c) The total number of subshells in a principal energy level?
d) Maximum number of electrons in a subshell?
2) Complete the table.
Elements | Atomic no.
(Z) |
Electronic
configuration |
N | 7 | —— |
—— | 9 | |
C | 6 | —— |
—— | 11 | 1S^{2} 2S^{2 }2P^{6} |
—— | 15 | |
Al | 13 | —— |
—— | 17 | —— |
Answer Key
Q.1) MCQ.
1) Which of the following originated quantum theory?
a) David Bohr
b) Ludwig Planck
c) Rutherford
d) Dobereiner
2) The maximum number of electrons that can be accommodate in M-shell is….?
a) 8
b) 10
c) 18
d) 32
3) Principal quantum number represented by…………?
a) k
b) l
c) m
d) n
4) Spectrum is a group of……………?
a) Frequency
b) Velocity
c) Wavelength
d) Speed
5) If l=2 for an atom, then number of orbitals in its sub-shell is……?
a) 2
b) 3
c) 4
d) 5
6) If l=0, then number of atom in its sub-shell is………?
a) 1
b) 2
c) 3
d) 0
Q.2) VERY SHORT ANSWER QUESTIONS
1) What is Hund’s rule?
→ The orbital of equal energy (degenerate) are occupied with one Electron each before pairing of electrons start.
2) Give Aufbau principal?
→ In The Ground state electronic configuration can be built up by Placing electrons in lowest available orbitals until total number of Electrons added is equal to atomic number.
3) Give electronic configuration of N & O?
→ Nitrogen (N) = 7
= 1S^{2}2S^{2}2P^{3}
Oxygen (O) = 8
= 1S^{2}2S^{2}2P^{4}
4) Give Pauli exclusion principal?
→ According to Pauli exclusion principal no two electrons of the same Atom can have all four quantum numbers the same.
5) What is electronic configuration?
→ The distribution of electrons in shells, sub-shells, and orbital in an Atom is known as electronic configuration.
6) What is the shape of orbital?
→ d – orbital is double – dumbbell in shape.
Q.3) SHORT ANSWER QUESTIONS.
1) Complete the table?
(l)
Cingular momentum quantum no. |
Subshell | Number of
Degenerated Orbitals |
0 | s | 1 |
1 | p | 3 |
2 | d | 5 |
3 | f | 7 |
2) What is Electromagnetic Spectrum?
→ Electromagnetic waves can have a wide variety of wavelengths.
The entire range of wavelength is known as on electromagnetic Spectrum.
This Spectrum consists of continuous range of wavelength of Gamma rays to the radio waves. But our eyes are sensitive only to visible light.
3) Which rule does not support in following diagram & draw diagram.
Q.4) LONG ANSWER QUESTIONS.
1) Answer the following questions.
a) Maximum number of electrons in principal energy level.
→ Principal energy level contains up to 2n^{2} electrons
Where n = number of shells.
b) maximum numbers of electrons in on orbital.
→ Two electrons.
c) The total number of subshells in a principal energy level?
→ 4 subshells. i.e., s, p, d, f.
d) Maximum number of electrons in a subshell?
→ Maximum number of electrons determined by formula
(2l + 1). L = number of subshells.
0 = s, 1 = p, 2 = d, 3 = f.
2) Complete the table.
Elements | Atomic no.
(Z) |
Electronic
configuration |
N | 7 | 1S^{2 }2S^{2} 2P^{3} |
F | 9 | 1S^{2 }2S^{2} 2P^{5} |
C | 6 | 1S^{2} 2S^{2 }2P^{2} |
Na | 11 | 1S^{2} 2S^{2 }2P^{6} |
P | 15 | 1S^{2} 2S^{2 }2P^{6} 3S^{2} 3P^{3} |
Al | 13 | 1S^{2} 2S^{2 }2P^{6} 3S^{2} 3P^{1} |
Cl | 17 | 1S^{2} 2S^{2 }2P^{6} 3S^{2} 3P^{5} |
Super super