Tag: RD Sharma Class 8 6th Chapter Solution

RD Sharma Class 8 Math 6th Chapter Algebraic Expressions and Identities Exercise 6.5 Solution

Exercise 6.5   Multiply: 1. (5x + 3) by (7x + 2) Solution: To multiply, we will use distributive law as follows: (5x+3)(7x+2) =5x(7x+2)+3(7x+2) =(5x×7x+5x×2)+(3×7x+3×2) =(35×2+10x)+(21x+6) =35×2+10x+21x+6 =35×2+31x+6 Thus, the answer is 35×2+31x+6 2. (2x + 8) by (x – 3) Solution: To multiply, we will use distributive law as follows: (2x+8)  (x–3) =  2x(x–3) […]

RD Sharma Class 8 Math 6th Chapter Algebraic Expressions and Identities Exercise 6.4 Solution

Exercise 6.4   Find the following products: 1. 2a3 (3a+5b) Solution: To find the product, we will use distributive law as follows: 2a3 (3a + 5b) = 2a3 × 3a + 2a3 × 5b = (2 x 3)(a3 × a) + (2 × 5)a3b = (2×3)a3+1+ (2×5)a3b = 6a4 +10a3b Thus, the answer is 6a4 +10a3b. 2. -11a (3a + 2b) Solution: To find the product, we will use distributive law as […]

RD Sharma Class 8 Math 6th Chapter Algebraic Expressions and identities Exercise 6.2 Solution

Exercise 6.2   1. Add the following algebraic expressions:  (i) 3a2b, −4a2b, 9a2b  Solution: To add the like terms, we proceed as follows: 3a2b + (-4a2b) + 9a2b = 3a2b – 4a2b + 9a2b                (Distributive Law) = 8a2b (iii) 4xy2–7x2y,12x2y–6xy2, −3x2y+5xy2 Solution: To add, we proceed as follows: (4xy2–7x2y)+(12x2y)+(−6xy2)+(−3x2y+5xy2) = 4xy2–7x2y+12x2y–6xy2–3x2y+5xy2 = 4xy2–6xy2+5xy2–7x2y+12x2y–3x2y      (Collecting like terms) = 3xy2+2x2y                 (Combining […]