Selina Concise Class 6 Math Chapter 6 Negative Numbers and Integers Exercise 6 Solution

Selina Concise Class 6 Math Chapter 6 Negative Numbers and Integers Exercise 6 Solution

EXERCISE 6

(1) Fill in the blanks:

(i) Negative of -20 is – (- 20) = + 20

(ii) Negative of 0 is 0.

(iii) Negative of 8 is – 8.

(iv) If 10 represents gain Rs 10, then – 10 represents loss Rs 10.

(v) If going south id negative then going north is positive.

(vi) Because 5<7, therefore – 5 > – 7.

(vii) If 3 > -2, then 3 is on the right side of – 2.

(viii) If – 8 < – 6, then – 8 is on the left side of – 6.

(2) Use a number line to write the following integers in descending order:

(3) Use a number line to write the following integers in descending order:

(4) Add:

(i) 13 + 15 = 28

(ii) – 13 + 15 = + 2

(iii) 13 + (– 15) = 13 – 15 = – 2

(iv) – 13 + (- 15) = – 13 – 15 = – 28

(5) Add:

(i) 259 + 214 = 473

(ii) – 528 – 243 = – 771

(iii) – 623 + 326 = – 297

(iv) 258 + (- 473) = 258 – 473 = – 215

(v) – 622 + (- 254) = – 622 – 254 = 876

(vi) 257 + (- 254) = 257 – 254 = 3

(6) Subtract:

(i) 8 – 5 = 3

(ii) 8 – (- 5) = 8 + 5 = 13

(iii) – 7 – 4 = – 11

(iv) – 8 – (- 2) = – 8 + 2 = – 6

(v) 12 – (- 3) = 12 + 3 = 15

(vi) – 3 – (- 6) = – 3 + 6 = 3

(7) Subtract:

(i) 453 – (- 123) = 453 + 123 = 576

(ii) -12 – (- 78) = – 12 + 78 = 66

(iii) – 124 – 329 = – 453

(iv) 0 – (- 222) = 222

(8) Using a number line, find the integer which is:

(i)  – 1 + 3 = 2

(ii) 2 – 5 = – 3

(iii) – 9 + 5 = – 4

(iv) – 4 – 4 = – 8

(v) 0 + 7 = 7

(vi) – 8 – 7 = – 15

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