Selina Concise Class 6 Math Chapter 6 Negative Numbers and Integers Exercise 6 Solution
EXERCISE 6
(1) Fill in the blanks:
(i) Negative of -20 is – (- 20) = + 20
(ii) Negative of 0 is 0.
(iii) Negative of 8 is – 8.
(iv) If 10 represents gain Rs 10, then – 10 represents loss Rs 10.
(v) If going south id negative then going north is positive.
(vi) Because 5<7, therefore – 5 > – 7.
(vii) If 3 > -2, then 3 is on the right side of – 2.
(viii) If – 8 < – 6, then – 8 is on the left side of – 6.
(2) Use a number line to write the following integers in descending order:
(3) Use a number line to write the following integers in descending order:
(4) Add:
(i) 13 + 15 = 28
(ii) – 13 + 15 = + 2
(iii) 13 + (– 15) = 13 – 15 = – 2
(iv) – 13 + (- 15) = – 13 – 15 = – 28
(5) Add:
(i) 259 + 214 = 473
(ii) – 528 – 243 = – 771
(iii) – 623 + 326 = – 297
(iv) 258 + (- 473) = 258 – 473 = – 215
(v) – 622 + (- 254) = – 622 – 254 = 876
(vi) 257 + (- 254) = 257 – 254 = 3
(6) Subtract:
(i) 8 – 5 = 3
(ii) 8 – (- 5) = 8 + 5 = 13
(iii) – 7 – 4 = – 11
(iv) – 8 – (- 2) = – 8 + 2 = – 6
(v) 12 – (- 3) = 12 + 3 = 15
(vi) – 3 – (- 6) = – 3 + 6 = 3
(7) Subtract:
(i) 453 – (- 123) = 453 + 123 = 576
(ii) -12 – (- 78) = – 12 + 78 = 66
(iii) – 124 – 329 = – 453
(iv) 0 – (- 222) = 222
(8) Using a number line, find the integer which is:
(i) – 1 + 3 = 2
(ii) 2 – 5 = – 3
(iii) – 9 + 5 = – 4
(iv) – 4 – 4 = – 8
(v) 0 + 7 = 7
(vi) – 8 – 7 = – 15