Selina Concise Class 6 Math Chapter 15 Decimal Fractions Exercise 15E Solution
EXERCISE 15E
(1) The cost of 1 fountain pen = Rs 13.25
∴ The cost of 8 such pens = Rs (13.25 × 8) = Rs 106.00
(2) The cost of 25 identical articles = Rs 218.25
∴ The cost of 1 article = Rs (218.25 ÷ 25) = Rs 8.73
(3) 4 pieces equal length of the iron rod is = 10.32 m
∴ 1 pieces length = (10.32 ÷ 4) = 2.58 m
(4) Cloth needed in 1 shirt = 2.15 m
∴ Cloth needed in 5 shirts = (2.15 × 5) = 10.75 m
(5) The boy walks 1 hour and he covered = 2.150 km
(6) The cost of 1 note-book = Rs 15.25
∴ Cost of 83 note-books = Rs (15.25 × 83) = Rs 1265.75
(7) Length of 1 bed cover = 2.1 m
∴ Length of 17 bed covers = (17 × 2.1) = 35.7 m
(8) Length of the 1st rope = 10 m 67 cm
Length of the 2nd rope = 16 m 32 cm
∴ Second rope longer than 1st rope,
= (16 m 32 cm – 10 m 67 cm)
= 5m 65 cm
(9) Weight of 12 soap = 5 kg 604 gm = (5 × 1000) + 604 = 5604 gm
(i) Weight of 1 soap = (5604 ÷ 12) = 467 gm
(ii) Weight of 5 cakes = (467 × 5) gm = (2335 ÷ 1000) kg = 2 kg 335 gm
(10) Total length of three strings,
= (50 m 75 cm) + (68 m 58 cm) + (121 m 3 cm)
= 240 m 63 cm
= (240 × 100) + 63 = 24063 cm
Then, this single string is divided into 12 equal pieces.
∴ Length of each piece = (24063 ÷ 12) = 2005.25 cm