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CBSEClass 5

S. K. Gupta Anubhuti Gangal Class 5 Math Eighth Chapter Decimals Exercise 30

By Net Explanations Last updated: May 31, 2022
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S. K. Gupta Anubhuti Gangal Class 5 Math Eighth Chapter Decimals Exercise 30

EXERCISE 30

Multiply:

Contents
S. K. Gupta Anubhuti Gangal Class 5 Math Eighth Chapter Decimals Exercise 30EXERCISE 30

(1) 4.67 by 3

= 4.67 × 3

= 14.01

(2) 7.42 by 5

= 7.42 × 5

= 37.1

(3) 5.93 by 8

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= 5.93 × 8

= 47.44

(4) 28.07 by 6

= 28.07 × 6

= 168.42

(5) 8.25 by 16

= 8.25 × 16

= 132

(6) 19.83 by 25       

= 19.83 × 25

= 495.75

(7) 615.3 by 78


= 615.3 × 78

= 47993.4

(8) 62.131 by 42

= 62.131 × 42

= 2609.502

(9) 723.04 by 89

= 723.04 × 89

= 64350.56

(10) If 5867 × 6 = 35202, then find the product of each of the following without actually performing multiplication.

(a) 5.867 × 6

= 35.202

(b) 58.67 × 6


= 352.02

(c) 586.7 × 6

= 3520.2

(d) 0.5867 × 6

= 3.5202

(11) If 1 liter of petrol costs Rs 45.34, find the cost of 25 liters.

Solution: The required cost of petrol (in Rs) = (45.34 × 25) = Rs 1133.50

(12) The cost of a pair of shoes is Rs 723.95. What will be cost of 38 such pairs of shoes?

Solution: The required cost of given pairs of shoes (in Rs) = (723.95 × 38) = 27510.10

TAGGED:CBSECBSE Decimals Ex 30Class 5DecimalsDecimals Class 5 Exercise 30 HomeworkDecimals Class 5 Exercise 30 solutionDecimals Class 5 SolutionMathematicsMathematics solutionMultiplication Of DecimalsS. K. Gupta Anubhuti GangalS. K. Gupta Anubhuti Gangal Class 5 Eighth Chapter SolutionS. K. Gupta Anubhuti Gangal Class 5 SolutionS. K. Gupta Anubhuti Gangal Decimals Exercise 30 HometaskWord Problems Of Decimals
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2 Comments
  • Mayank says:
    August 21, 2020 at 12:58 pm

    Please make a video of Math steps-5 exercise-29 to 30

    Reply
  • Astha singh says:
    October 20, 2020 at 8:41 am

    Good

    Reply

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