**S Chand ICSE Mathematics Class 9 Solution Seventh Chapter Logarithms Exercise 7B**

**(1) Express each sum or difference as a single logarithm.**

**(i) log 6 + log 5**

= log (6 x 5) = log30

**(ii) log 12 – log 2**

= log (12/2)

= log6

**(iii) log _{3} 5 + log_{3} 2 + log_{3} 4**

= log_{3} (5 x 2 x 4)

= log_{3} 40

**(iv) log _{2} 12 – log_{2} 2 + log_{2} 5**

= log_{2} (12 x 5 ÷ 2)

= log_{2} 30

**(5) log _{10} n + log_{10 }5 = 1**

**(ii) log _{3} n – log_{3} 4 = 2**

**(iii) log _{6} n – log_{6} (n-1) = log_{6} 3**

**(iv) 2 log x = 4 log 3**

**Solution: **

(6) (i) log_{10} 5 + log_{10}2

= log_{10}(5 x 2)

= log_{10}10

= 1

**(ii) log _{10 }4 + log_{10 }5 + log_{10 }2**

= log_{10} 20 – log_{10} 2

= log_{10} 20 – log_{10} 2

= log_{10} (20/2)

= log_{10} 10

= 1

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