S Chand ICSE Mathematics Class 6 Solution Sixth Chapter Decimal Fractions Exercise 6C
(1) (i) 8 P = 1 hundredth of a rupee = 8/100 x 1 = 0.08
(ii) 19 P = 19 hundredths of a rupee = 19/100 x 1 = 0.19
(iii) 75 P = 75 hundredths of a rupee = 75/100 x 1 = 0.75
(iv) 10 P = 0.10
(v) 7.43
(vi) 28.06
(vii) 509.95
(viii) 127.80
(2) (i) 6 mm = 6/10 cm = 0.6 cm
(ii) 9 mm = 9/10 cm = 0.9 cm
(iii) 42 mm = 42 / 10 = 4.2 cm
(iv) 375 mm = 375 / 10 = 37.5 cm
(3) (i) 7 cm = 7 / 100 m = 0.07 m
(ii) 18 cm – 18/100 m = 0.18 m
(iii) 195 cm = 195 / 100 m = 19.5 m
(iv) 1328 cm = 1328 / 100 m = 13.28 m
(4) (i) 8 m = 8 / 1000 km = 0.008 km
(ii) 39 m = 39 / 1000 km = 0.039 km
(iii) 457 m = 457 / 1000 km = 0.457 km
(iv) 3824 m = 3824 / 1000 km = 3.824 km
(5) (i) 6.15
(ii) 65 m 9 cm = 65 + 9/100 = 65 + 0.09 = 65.09 m
(iii) 12 km + 200 / 1000 = 12 km + 0.200 = 12.200 km
(iv) 105 km + 25/1000 = 105 km + 0.025 km = 105.025 km
(v) 829 cm = 829 / 100000 km = 0.00829 km
(6) (i) 18 mg = 18 / 1000 g = 0.018 g
(ii) 125 mg = 125 / 1000 g = 0.125 g
(iii) 6 mg = 6 / 1000 g = 0.006 g
(iv) 18 g 12 mg = 18 g + 12 / 1000 = 18 g + 0.012 g = 18.012 g
(v) 9 g 77 mg = 9 g + 77 / 1000 g = 9 g + 0.077 = 9.077g
(7)(i) 690 g = 690 / 1000 kg= 0.690 kg
(ii) 97 g = 97 / 1000 kg = 0.097 kg
(iii) 2790 g = 2790 / 1000 kg = 2.790 kg
(iv) 1700 g = 1700 / 1000 kg = 1.700 kg
(v) 4 g = 4 / 1000 kg = 0.004 kg
(vi) 4 kg 25 g = 45 kg + 25 /1000 kg = 45 kg + 0.025 kg = 45.025 kg
(vii) 23 kg 179 g
= 23 kg + 179 / 1000 kg
= 23 kg + 0.179 kg
= 23.179 kg
(viii) 110 kg 8 g
= 110 kg + 8 /1000 kg
= 110 kg + 0.008 kg
= 110.008 kg
(8) (i) 5 ml
= 5 / 1000 l
= 0.005 l
(ii) 732
= 732 / 1000
= 0.732 l
(iii) 19 l
= 19 / 1000 kl
= 0.019 kl
(iv) 15 l 25 ml
= 15 l + 25 / 1000 l
= 15 l + 0.025
= 15.025 l
(v) 4 kl 289 l
= 4 kl + 289 / 1000 kl
= 4 kl + 0.289 kl
= 4.289 kl
The distance between Dhruv’s office and home is 7 km 5 m. He walks 1 km 125 m to the metro station A The distance travelled by metro to metro station B is 4 km 65 m. What distance does he have to wa from the metro station B to the office? Give your answer in kilometres.
7 km 5 m
7000 m + 5 m = 7005 m
1 km 125 m
4 km 65 m
5 km 190m = 5000 + 190 = 5190 m
distance does he have to wa from the metro station B to the office 7005 m – 5190 m = 1815 m = 1 km 815 m
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