S Chand ICSE Mathematics Class 6 Solution Second Chapter Natural Numbers and Whole Numbers Exercise 2D (O.P. Malhotra, S.K. Gupta, Anubhuti Gangal)

S Chand ICSE Mathematics Class 6 Solution Second Chapter Natural Numbers and Whole Numbers Exercise 2D (O.P. Malhotra,  S.K. Gupta, Anubhuti Gangal)

Exercise 2D

(1) FILL IN THE BLANKS WITH A WHOLE NUMBER TO MAKE EACH OF THE FOLLOWING A TRUE STATEMENT:

(a)23987 x 0 = 0

(b) 59083 x 1 = 59083

(c) 879 x 56 = 56 x 879

(d) 100x100x10=100000

(e) 27x98x35=35x98x27

(f)87×19=19x(80+7)

(g) 205×69=69×200+5

(2) FILL IN THE BLANKS :

(a) 56×39=56x(30+9)+56×9

(b) 37×19=37x(10+9)+37×5+37×9

(c) 18 x 47=18 x (50-3)-18×3

(d) 76×88=76x(90-2)-76×2

(3) WHAT NUMBER SHOULD REPLACE EACH n ?

(1) (a) 3 (n+6)=(3×5)+(3×6)

Sol) 3n+18=15+18

Or,3n+18=33-18

Or,3n= 15

Or, n=15/3 =5

(b) (7×4)+(nx3)=7(4+3)

Sol) 28+3n=28+21

Or, 3n= 49-28

Or, n=21/3 =7

(4) MULTIPLY BY SUITABLE ARRANGEMENT:

(a)  (5×8)x7x25=56x7x25= 392×25=9800

(b) (25×4)x598= 100×598=59800

(c)(250×4)x2893=1000×2893=2893000

(d)(2867×2)x50= 5734×50=286700

(e)(125×8)x786= 1000×786=786000

(f)(625×16)x3982 =10000×3982=39820000

(g) (80×5)x394=400×394=157600

(h) (15×8)x40x225=120x40x225=1080000

(i) (16×80)x25x15237=1280x24x15237=468080640

(5) FIND EACH OF THE FOLLOWING PRODUCTS BY USING PROPERTIES OF MULTIPLICATION :

(a) 972×8+972×2= 7776+1944=9720

(b) 982×46+27×982-58×982-15×982=45172+26514-56956-14730=45172+26514+71686=143372

(c)957x10x583-483×9570= 957x10x100x9570=9158490000

(6) USING PROPERTIES OF ADDITION AND MULTIPLICATION, FIND EACH OF THE FOLLOWING PRODUCTS.

(a) 928×857 = (900+20+8)x857) = 795296

(b)3046×729 = (3000+40+6)x729 = 2220534

(c) 849×205 = (800+40+9)x205 = 174045

(d)367×10004 = (300+60+7)x10004= 3671468

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