RS Aggarwal Vikash Aggarwal Class 4 Activity Book Composite Mathematics Activity Sheet 93 Solution
Activity Sheet – 93
Solve the following word problems:
(1) Find the perimeter of a rectangle with length 5 cm 8 mm and breadth 4 cm 2 mm.
Solution: Here, 5 cm 8 mm = (50 + 8) mm = 58 mm
And, 4 cm 2 mm = (40 + 2) mm = 42 mm
Perimeter of the rectangle = 2 × (58 + 42) mm
= 2 × 100 mm = 200 mm = 20 cm
(2) Find the perimeter of a square each of whose sides is 26 cm long.
Solution: Perimeter of the square = (4 × 26) cm = 104 cm = 1 m 4 cm
(3) The perimeter of a rectangle is 46 cm. The length of the rectangle is 13 cm. What is its breadth?
Solution: Let the breadth be a cm.
∴ 2 (13 + a) = 46
⇒ 26 + 2a = 46
⇒ 2a = 46 – 26
⇒ a = 20/2=10
Therefore, the breadth is 10 cm.
(4) What is the length of the side of a square whose perimeter is 48 cm?
Solution: Let the length of the side be x cm.
∴ 4x = 48
⇒ x = 48/4=12
Hence, the length of the square is 12 cm.