## RS Aggarwal Class 6 Math Third Chapter Whole Numbers Exercise 3E Solution

## EXERCISE 3E

**(1) Divide and check your answer by the corresponding multiplication in each of the following:**

**(i) 1936 ****÷16 **

Solution:

**Ans:** 121.

**(ii) 19881 ****÷ 47**

**Ans:** 423.

**(iii) 257796 ****÷ 341**

**Ans:** 756

**(iv) 612846 ****÷ 582**

**Ans:** 1053.

**(v) 34419 ****÷ 149**

**Ans:** 231

**(vi) 39039 ****÷ 1001**

**Ans:** 39

**(2) Divide, and find out the quotient and remainder. Check your answer.**

**(i) 6971 ****÷ 47**

Solution:

**Ans:** So the quotient= 147 and remainder= 22.

**(ii) 4178 ****÷ 35**

**Ans:** So, the quotient= 119 and remainder= 13.

**(iii) 36195 ****÷ 153**

**Ans:** So, the quotient= 236 and remainder= 87.

**(iv) 93575 ****÷ 400**

**Ans: **So, the quotient= 208 and remainder= 375.

**(v) 230254 ****÷ 1000**

**Ans:** So, the quotient= 230 and remainder= 254.

**(vi) 16135 ****÷ 875**

**Ans:** So, the quotient= 18 and remainder= 385 .

**(3) Find the value of**

**(i) 65007 ****÷ 1**= 65007.

**(ii) 0 ****÷ 879**= 0.

**(iii) 981 + 5720 ****÷ 10**

= 981 + 572

= 1553.

**(iv) 1507 – (625 ****÷ 25)**

= 1507 – 25

= 1482.

**(v) 32277 ****÷ (648 – 39)**

= 32277 ÷ 609

= 53.

**(vi) (1573 ****÷ 1573) – (1573 ÷ 1573)**

= 1 – 1

= 0.

**(4) Find a whole number n such that n ÷ n = n.**

** Ans: **

nn

= 1

So, n = 1.

**(5) The product of two numbers is 504347. If one of the numbers is 317, find the other. **

**Ans: **The other numb er is

So, the other number is 1591.

**(6) On dividing 59761 by a certain number, the quotient is 189 and the remainder is 37. Find the divisor **

Solution: Let the divisor is m.

Thus, Dividend= (Division x Quotient) + Remainder

Or, 59761= (m x 189) + 37

Or, 189 m= 59761-37

Or, m=

59724189

Or, m= 316.

Therefore, the division (m)= 316.

**(7) On dividing 55390 by 299, the remainder is 75. Find the quotient using the division algorithm.**

Solution: The quotient is m.

Thus, Dividend = ( divisor x quotient) + remainder

Or, 55390 = (299 x m) + 75

Or, 299 m = 55390 – 75

Or, m =

55313299

Or, m = 185

Therefore, the quotients (m)= 185.

**(8) What least number must be subtracted from 13601 to get a number exactly divisible by 87?**

Solution:

**Ans:** 29 subtracted from 13601 to get the number which is divisible by 87.

**(9) What least number must be added to 1056 to get a number exactly divisible by 23?**

Solution: Here, 23 x 45= 1035, 23 x 46= 1058

We have 1056 that means (1058 – 1056)= 2. If 2 is added to 1056 to get the number that divisible by 23.

**(10) Find the largest 4-digit number divisible by 16.**

**Ans:** 9984.

**(11) Divide the largest 5 digit number by 653. Check your answer by the division algorithm.**

Solution:

Ans: Quotient= 153, remainder= 90.

**(12) Find the largest 6-digit number exactly divisible by 83.**

**Ans:** 100015.

**(13) 1 dozen bananas cost RS 29. How many dozens can be purchase for RS 1392?**

Solution: 1 dozen= 12

Therefore, 1392 ÷ 12= 116.

**Ans:** 116 bananas can be purchase for Rs 1392.

**(14) 19625 trees have been equally planted in 157 rows. Find the number of trees in each row.**

Solution: 19625 ÷ 157= 125.

**Ans:** 125 trees have been planted in each row.

**(15) The population of a town is 517530. If one out every 15 is reported to be literate, find how many literate persons are there in the town.**

Solution: 517530 ÷ 15= 34502.

**Ans:** 34502 persons are literate in the town.

**(16) The cost price of 23 colour television sets is RS 570055. Determine the cost price of each TV set if each costs same.**

Solution: 5700555 ÷ 23= 24785.

**Ans:** The cost of each TV is RS 24785.

It’s very helpful for us, the students!

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