# RS Aggarwal Class 6 Math Seventh Chapter Decimals Exercise 7D Solution

## EXERCISE 7D

Subtract:

(1) 27.86 from 53.74

Solution: Converting the given decimals into like decimals, we get 27.86 and 53.74

Writing them in column form with the larger one at the top and subtracting, we get:

53.74
-27.86
25.88

(2) 64.98 from 103.87

Solution: Converting the given decimals into like decimals, we get 64.98 and 103.87

Writing them in column form with the larger one at the top and subtracting, we get:

103.84
-64.98
38.89

(3) 59.63 from 92.4

Solution: Converting the given decimals into like decimals, we get 59.63 and 92.40

Writing them in column form with the larger one at the top and subtracting, we get:

92.40
-59.63
32.77

(4) 56.8 from 204

Solution: Converting the given decimals into like decimals, we get 56.8 and 204.0

Writing them in column form with the larger one at the top and subtracting, we get:

204.4
-56.8
147.2

(5) 127.38 from 216.2

Solution: Converting the given decimals into like decimals, we get 127.38 and 216.20

Writing them in column form with the larger one at the top and subtracting, we get:

216.20
-127.38
88.82

(6) 39.875 from 70.68

Solution: Converting the given decimals into like decimals, we get 39.875 and 70.680

Writing them in column form with the larger one at the top and subtracting, we get:

70.680
-39.875
30.805

(7) 348.237 from 523.12

Solution: Converting the given decimals into like decimals, we get 348.237 and 523.120

Writing them in column form with the larger one at the top and subtracting, we get:

523.120
-348.237
174.883

(8) 458.573 from 600

Solution: Converting the given decimals into like decimals, we get 458.573 and 600.000

Writing them in column form with the larger one at the top and subtracting, we get:

600.000
-458.573
141.427

(9) 149.456 from 206.321

Solution: Converting the given decimals into like decimals, we get 149.456 and 206.321

Writing them in column form with the larger one at the top and subtracting, we get:

206.321
-149.456
56.865

(10) 0.612 from 3.4

Solution: Converting the given decimals into like decimals, we get 0.612 and 3.400

Writing them in column form with the larger one at the top and subtracting, we get:

3.400
-0.612
2.788

Simplify:

(11) 37.6 + 72.85 – 58.678 – 6.09

= (37.600 + 72.850) – (58.678 +6.090)     [converting like decimals]

= 110.45 – 64.768

= 45.682

(12) 75.3 – 104.645 + 178.96 – 47.9

= (75.300 + 178.960) – (104.645 + 47.900)       [converting like decimals]

= 254.26 – 152.545

= 101.715

(13) 213.4 – 56.84 – 11.87 – 16.087

= 213.400 – (56.840 + 11.870 + 16.087)     [converting like decimals]

= 213.400 – 84.797

= 128.603

(14) 76.3 – 7.666 – 6.77

= 76.300 – (7.666 + 6.770)    [converting like decimals]

= 76.300 – 14.436

= 61.864

(15) What is to be added to 74.5 to get 91?

Solution: Converting the given decimals into like decimals, we get 74.5 and 91.0

So, (91.0 – 74.5) = 16.5

Ans: 16.5 is to be added to 74.5 to get 91.

(16) What is to be subtracted from 7.3 to get 0.862?

Solution: Converting the given decimals into like decimals, we get 7.300 and 0.862

So, (7.300 – 0.862) = 6.438

Ans: 6.438 is to be subtracted from 7.3 to get 0.862

(17) By how much should 23.754 decreased to get 50?

Solution: Converting the given decimals into like decimals, we get 23.754 and 50.000

So, (50.000 – 23.754) = 26.246

(18) By how much should 84.5 be decreased to get 27.84?

Solution: : Converting the given decimals into like decimals, we get 84.50 and 27.84

So, (84.50 – 27.884) = 56.66

(19) If the school bags of Neelam and Garima weigh 6 kg 80 g and 5 kg 265 g respectively, whose bag is heavier and by how much?

Solution: We have:

Weigh of Neelam’s bag 6.080 kg

Weigh of Garima’s bag 5.265 kg

So, (6.080 – 5.265) = 0.815 kg = 815 g

Hence,815 g Neelam’s bag is heavier from Garima’s bag.

(20) Kunal purchased a notebook for Rs 19.75, a pencil for Rs 3.85 and a pen for Rs 8.35 from a book shop. He gave a 50-rupee note to the shopkeeper. What amount did he get back?

Solution: Total money paid = 50.00 rupee

Cost of notebook = 19.75 rupee

Cost of pencil = 3.85 rupee

Cost of pen = 8.35 rupee

Thus, 50.00 – (19.75 + 3.85 + 8.35)

= 50.00 – 31.95

= 18.05

Hence, kunal get back 18.05 rupee.

(21) Sunita purchased 5 kg 75 g of fruits and 3 kg 465 g of vegetables, and put them in a bag. If this with these contents weighs 9 kg, find the weight of the empty bag.

Solution: The contents weigh of bag = 9.000 kg

The weight of fruits = 5.075 kg

The weight of vegetables = 3.465 kg

Thus, 9.000 – (5.075 + 3.465)

= 9.000 – 8.540

= 0.46 kg = 460 g

Hence, the weight of the empty bag is 460 g.

(22) The distance between Reeta’s house and her office is 14 km. She covers 10 km 65 m by scooter, 3 km 75 m by bus and the rest on foot. How much distance does she cover by walking?

Solution: Distance covered by scooter = 10.65 km

Distance covered by bus = 3.75 km

Total distance covered by scooter and bus = (10.65 + 3.75) = 13 km 140 m

Total distance to be covered by Reeta = 14.0 km

Distance covered by walking = 14.000 – 13.140 = 0.860 km = 860 m

Updated: May 30, 2022 — 12:23 pm