## RS Aggarwal Class 6 Math Seventh Chapter Decimals Exercise 7D Solution

## EXERCISE 7D

Subtract:

**(1) 27.86 from 53.74**

Solution: Converting the given decimals into like decimals, we get 27.86 and 53.74

Writing them in column form with the larger one at the top and subtracting, we get:

53.74

__-27.86__

25.88

**(2) 64.98 from 103.87**

Solution: Converting the given decimals into like decimals, we get 64.98 and 103.87

Writing them in column form with the larger one at the top and subtracting, we get:

103.84

__-64.98
38.89__

**(3) 59.63 from 92.4**

Solution: Converting the given decimals into like decimals, we get 59.63 and 92.40

Writing them in column form with the larger one at the top and subtracting, we get:

92.40

__-59.63
__ 32.77

**(4) 56.8 from 204**

Solution: Converting the given decimals into like decimals, we get 56.8 and 204.0

Writing them in column form with the larger one at the top and subtracting, we get:

204.4

__-56.8
147.2__

**(5) 127.38 from 216.2**

Solution: Converting the given decimals into like decimals, we get 127.38 and 216.20

Writing them in column form with the larger one at the top and subtracting, we get:

216.20

__-127.38__

__ 88.82__

**(6) 39.875 from 70.68**

Solution: Converting the given decimals into like decimals, we get 39.875 and 70.680

Writing them in column form with the larger one at the top and subtracting, we get:

70.680

__-39.875__

30.805

**(7) 348.237 from 523.12**

Solution: Converting the given decimals into like decimals, we get 348.237 and 523.120

Writing them in column form with the larger one at the top and subtracting, we get:

523.120

__-348.237
__ 174.883

**(8) 458.573 from 600**

Solution: Converting the given decimals into like decimals, we get 458.573 and 600.000

Writing them in column form with the larger one at the top and subtracting, we get:

600.000

__-458.573__

__ 141.427__

**(9) 149.456 from 206.321**

Solution: Converting the given decimals into like decimals, we get 149.456 and 206.321

Writing them in column form with the larger one at the top and subtracting, we get:

206.321

__-149.456
56.865__

**(10) 0.612 from 3.4**

Solution: Converting the given decimals into like decimals, we get 0.612 and 3.400

Writing them in column form with the larger one at the top and subtracting, we get:

3.400

__-0.612
2.788__

Simplify:

**(11) 37.6 + 72.85 – 58.678 – 6.09 **

= (37.600 + 72.850) – (58.678 +6.090) [converting like decimals]

= 110.45 – 64.768

= 45.682

**(12) 75.3 – 104.645 + 178.96 – 47.9**

= (75.300 + 178.960) – (104.645 + 47.900) [converting like decimals]

= 254.26 – 152.545

= 101.715

**(13) 213.4 – 56.84 – 11.87 – 16.087**

= 213.400 – (56.840 + 11.870 + 16.087) [converting like decimals]

= 213.400 – 84.797

= 128.603

**(14) 76.3 – 7.666 – 6.77**

= 76.300 – (7.666 + 6.770) [converting like decimals]

= 76.300 – 14.436

= 61.864

**(15) What is to be added to 74.5 to get 91?**

Solution: Converting the given decimals into like decimals, we get 74.5 and 91.0

So, (91.0 – 74.5) = 16.5

Ans: 16.5 is to be added to 74.5 to get 91.

**(16) What is to be subtracted from 7.3 to get 0.862?**

Solution: Converting the given decimals into like decimals, we get 7.300 and 0.862

So, (7.300 – 0.862) = 6.438

Ans: 6.438 is to be subtracted from 7.3 to get 0.862

**(17) By how much should 23.754 decreased to get 50?**

Solution: Converting the given decimals into like decimals, we get 23.754 and 50.000

So, (50.000 – 23.754) = 26.246

**(18) By how much should 84.5 be decreased to get 27.84?**

Solution: : Converting the given decimals into like decimals, we get 84.50 and 27.84

So, (84.50 – 27.884) = 56.66

**(19) If the school bags of Neelam and Garima weigh 6 kg 80 g and 5 kg 265 g respectively, whose bag is heavier and by how much?**

Solution: We have:

Weigh of Neelam’s bag 6.080 kg

Weigh of Garima’s bag 5.265 kg

So, (6.080 – 5.265) = 0.815 kg = 815 g

Hence,815 g Neelam’s bag is heavier from Garima’s bag.

**(20) Kunal purchased a notebook for Rs 19.75, a pencil for Rs 3.85 and a pen for Rs 8.35 from a book shop. He gave a 50-rupee note to the shopkeeper. What amount did he get back?**

Solution: Total money paid = 50.00 rupee

Cost of notebook = 19.75 rupee

Cost of pencil = 3.85 rupee

Cost of pen = 8.35 rupee

Thus, 50.00 – (19.75 + 3.85 + 8.35)

= 50.00 – 31.95

= 18.05

Hence, kunal get back 18.05 rupee.

**(21) Sunita purchased 5 kg 75 g of fruits and 3 kg 465 g of vegetables, and put them in a bag. If this with these contents weighs 9 kg, find the weight of the empty bag.**

Solution: The contents weigh of bag = 9.000 kg

The weight of fruits = 5.075 kg

The weight of vegetables = 3.465 kg

Thus, 9.000 – (5.075 + 3.465)

= 9.000 – 8.540

= 0.46 kg = 460 g

Hence, the weight of the empty bag is 460 g.

**(22) The distance between Reeta’s house and her office is 14 km. She covers 10 km 65 m by scooter, 3 km 75 m by bus and the rest on foot. How much distance does she cover by walking?**

Solution: Distance covered by scooter = 10.65 km

Distance covered by bus = 3.75 km

Total distance covered by scooter and bus = (10.65 + 3.75) = 13 km 140 m

Total distance to be covered by Reeta = 14.0 km

Distance covered by walking = 14.000 – 13.140 = 0.860 km = 860 m