# Exercise 13.2

### 1. Find the S.P.

(i) P = Rs.13000 and Discount = 10%

(ii)  M.P = Rs.500 and Discount = 15%

### (i) p = Rs. 13000 and Discount = 10%

We know that S.P = M.P – Discount S.P = Rs (1300-130) = Rs. 1170

### (ii) M.P = Rs. 500 and Discount = 15%

We know that S.P= M.P  – Discount S.P = Rs. (500-75) = Rs. 425

### 2. Find the M.P., if

(i) S.P. = Rs. 1222 and Discount = 6%

(ii) S.P. = Rs. 495 and Discount = 1%

#### Solution:  ### 3. Find the discount in percent.

(i) P = Rs.900 and S.P = Rs.873

(ii) P = Rs.500 and S.P = Rs.425

### (i) P = Rs.900 and S.P = Rs.873

We know that,

S.P = M.P – discount

= 873 = 900 – discount

= Discount = (900-873)=Rs. 27 = 100

= 3%

### (ii) P = Rs 500 and s.p = Rs. 425

We know that,

S.P = M.P- Discount

= 425 = 500 – Discount

= discount = (500-425) = Rs. 75 ### 4. A shop selling sewing machines offers 3% discount on all cash purchases. What cash amount does a customer pay for a sewing machine the price of which is marked as Rs.650?

#### Solution:

Discount = 3%

Market price = Rs. 650 = Rs. 19.50

So, M.P = M.P – Discount

= 650 – 19.50

= Rs. 630.50

### 5. The marked price of a ceiling fan is Rs. 720. During off season, it is sold for Rs. 684. Determine the discount percent.

#### Solution:

Given,

Marked price = 720

Selling price = 684

Discount = M.P. – S.P.

= 720 – 684 = 36 Discount= 5%

### 6. On the eve of Gandhi Jayanti, a saree is sold for Rs.720 after allowing 20% discount. What is the market price?

#### Solution:

Given, S.P OF THE SAREE =Rs. 720

Discount on the saree = 20% Since, S.P = M.P – discount

= 720 = x – 0.20(720)

= x = Rs. 900

Thus the M.P of the saree is Rs. 900

### 7. After allowing a discount of 712%on the market price , an article is sold for Rs.555. find the marked price.

#### Solution:

Given, Selling Price of the article = Rs. 555

Discount = 7.5%

Let the Marked price of the article be Rs. x = Rs. 0.075x

Selling Price = Market price – Discount

= 555 = x- 0.075x

= x = Rs. 600

Thus, the Market price of the article is Rs.600

### 8. A shopkeeper allows his customers 10% off on the marked price of goods and still gets a profit of 25%. What is the actual cost to him of an article marked Rs.250?

#### Solution:

Let the C.P of the article be RS. X

M.P. of the article = – Rs. 250

Discount = 10%

Discount = 10% of 250 =Rs. 180

The C.P of the article is Rs. 180

### 9. A shopkeeper allows 20% off on the marked price of goods and still gets a profit of 25%. What is the actual cost to him of an article marked as Rs.500?

#### Solution:

Given,

M.P of the an article = Rs.500

Discount = 20%

Therefore, discount = 20% of 500 = Rs. 320

The actual cost price of the article is Rs. 320.

### 10. A tradesman marks his goods at such a price that after allowing a discount of 15%, he makes a profit of 20%. What is the marked price of an article whose cost price is Rs. 170?

#### Solution:

Given,

C.P of the article = 170 Rs.

Profit = 20% M.P. = 240/-

### 11. A shopkeeper marks his goods at such a price that after allowing a discount of 25% on the marked price, he still makes a profit of 50%. Find the ratio of the C.P to the M.P

#### Solution:

Let the C.P be Rs. x

Let the M.P be Rs. y

Gain % = 50% C.P : M.P = 1.2

### 12. A cycle dealer offers a discount of10% and still makes a profit of 26%. What is the actual cost to him of a cycle whose marked price is Rs.840?

#### Solution:

Given,

M.P of the cycle = Rs. 840

Discount = 10%

So, S.P = M.P – Discount

= 840 –

= Rs. 756

S.P = Rs. 756

Gain = 26% = Rs. 600

Hence, the C.P of the cycle is Rs. 600

### 13. A shopkeeper allows 23% on commission on his advertised price and still makes a profit of 10%. If he gains Rs.56 on one item, find his advertised price.

#### Solution:

Let us consider the Cost price of the item be = Rs .y

Profit% = 10%

Profit = 10% 0f y = Rs. 1.1y

And also, profit = Selling Price – Cost Price

= Rs. (1.1 y-y) = Rs. 0.1y

We get,

= 0.1y=56

= y= Rs. 560

The Advertised price = Rs. 800

The Advertised of the item is Rs. 800

### 14. A shopkeeper marked his goods at 40% above the cost price but allows a discount of 5% for cash payment to his customers. What actual profit does he make, if he receive Rs. 1064 after pating the discount?

#### Solution:

Given,

Shopkeeper marks his goods at 40% above the cost price.

Let cost price e ‘X’ X = 800

Cost price is 800

Selling is 1064

Profit price is 1064

Profit will be = 1064-800=264/-

### 15. By selling a pair of earrings at a discount of 25% on the marked price, a jeweler makes a profit of 16%.if the profit is Rs.48, what is the cost price? What is the marked price and the price at which the pair was eventually bought?

#### Solution:

Let the cost price of the pair of the earrings Rs. X

Profit = 16% = Rs. 464

Thus, C.P of the pair of earrings = Rs. x = Rs. 300

S.P of the pair of earrings = Rs. x = Rs. 300

S.P of the pair of earrings = Rs. 348

M.P of the pair earrings = Rs. 464

### 16. A publisher gives 32% discount on the printed price of a book to booksellers. What does a bookseller pay for a book whose printed price is Rs.275?

#### Solution:

Discount allowed by the publisher = 32% on the printed price

Printed price = Rs. 275

So. 32% of Rs. 275 = Rs. 88

The bookseller pays = Rs. 275 – Rs 88

= Rs. 187

The bookseller pays Rs. 187 for a book

### Solution:

Let the cost price of the lamp be RS. 100

Loss= 10% of cost price

Selling Price = Cost Price – loss

= Rs.100 – Rs. 10

= RS. 90

The trader allows a discount of 20% which would be when the M.P is Rs. 100, the Selling Price will be Rs. 80

So, Rs. 80 is the Selling Price, the Marked price = Rs. 100 If Res.1 is the Selling Price, So Marked price = Rs.

Rs. 90 is the Selling Price Then, Market price = R.s.

= Rs. 11250

Hence, the trader marks his goods at 12.5% above the cost price.

### 18. The list price of a table fan is Rs. 480 and it is available to a retailer at 25% discount. For how much should a retailer sell it to gain 15%?

#### Solution:

Given,

List price of table fan = Rs 480

M.P. = 480

Retailer buys it at discount 25% S.P. = 414

Retailer should it for Rs 414 to get 15% gain

### 19. Rohit buys an item at 25% discount on the marked price. He sells it for Rs.660, making a profit of 10%. What is the marked price of the item?

#### Solution:

Given, S.P of the item = Rs. 660

Discount On the item = 25 %

Profit on the item = 25%

Profit on the item = 10%

Discount = 25% of S.P = Rs. 880

Thus, the market price of item is Rs. 880

### 20. A cycle merchant allows 20% discount on the marked price of the cycles and still makes a profit of 20%. If he gains Rs.360 over the sale of one cycle, find the marked price of the cycle?

#### Solution: ### 21. Jyoti and Meena run a ready-made garment shop. They mark the garments at such a price that even after allowing a discount of 12.5%, they make a profit of 10%. Find the marked price of a suit which costs them Rs.1470.

#### Solution: ### 22. What price should Aslam mark on a pair of shoes which costs him Rs.1200 so as to gain 12% after allowing a discount of 16%?

#### Solution:

Given, C.P of the pair of shoes = Rs. 1470

Gain = 12%

Discount = 16% = Rs. 1600

Aslam should sell the pair of shoes for Rs. 1600

### 23. Jasmine allows 4% discount on the marked price of her goods and still earns a profit of 20%. What is the cost price of a shirt for her marked as Rs.850?

#### Solution:

Given, M.P of the shirt = Rs. 850

Discount = 4% = Rs. 680

Thus, the cost of the shirt is Rs. 680

### 24. A shopkeeper offers 10% off-season discount to the customers and still makes a profit of 26%. What is the cost price for the shopkeeper on a pair of shoes marked at Rs.1120?

#### Solution:

Given,

M.P of the Pair of shoes = Rs. 1120

Discount = 10% = Rs. 800

The cost price of the pair of shoes will be Rs. 800

### 25. A lady shopkeeper allows her customers 10% discount on the marked price of the goods and still gets a profit of 25%. What is the cost price of a fan for her marked at Rs. 1250

#### Solution:

Given,

M.P of the fan = Rs. 1250

Discount = 10%

So, The cost price of fan fan= Rs. 900

Updated: November 29, 2019 — 3:38 pm