RD Sharma Class 7 Math First Chapter Integers Exercise 1.2 Solution

Exercise 1.2

 

2. Divide:

 

(i) 102 by 17

Solution:

Give 102 by 17

We can write given question as 102 17

102 17= |102/17| = |102|/|17 [By applying the mod]

= 102/17 = 6

(ii) –85 by 5

Solution:

Given –85 by 5

We can write given question as -85  5

-85/5 = -17 = |-85/5|= |-85|/|5| [by applying the mod]

(iii) –161 by –23

Solution:

Given -161 by -23

We can write question as -161

– 16-23 = |-161/-23|= |-161|/|-23| [by applying the mod]

= 161/23= 7

(iv) 76 by –19

Solution:

Given 76 by –19

We can write given question as 76-19

76-19 = |76/-19| = |76|/|-19| [by applying the mod]

(v) 17654 by –17654

Solution:

Given 17654 by –17654

We can write given question as 17654 -17654

17654 -17654 = | 17654/-17654| = 17654|/| -17654| [by applying the mod]

(vi) (–729) by (–27)

Solution:

Given (-729) by (-27)

We can write given question as 21590 -10

21590/-10 = | 21590 / -10| = |21590|/|-10| [by applying the mod ]

= 21590 / -10 = -2159

(vii) 21590 by – 10

Solution:

Given 21590 by -10

We can write given question as 21590 ÷ -10

21590 ÷ -10 = |21590/-10| = |21590|/|-10| [by applying the mod]

= 21590/-10 = -2159

(viii) 0 by –135

Solution:

Given 0 by -135

We can write given question as 0-135

0-135 = 0 [because anything is divided by 0we get result as 0]

2. Fill in the blanks:

 

 (i) 296 ÷ …. = – 148

Solution:

We have,

(ii) – 88 ÷ …. = 11

Solution:

(iii) 84 ÷ …. = 12

Solution:

84/12 = 7

(iv)  …. ÷ -5 = 25

Solution:

25 × (- 5) = – 125

(v) …. ÷ 156 = – 2

Solution:

– (156 × 2)

= – 312

(vi) x/567 = – 1

Solution:

⇒ x = – (567 × 1)

= – 567

∴ – (567/567) = -1

3. Which of the following statements are true?

(i) 0 ÷ 4 = 0

(ii) 0 ÷ (-7) = 0

(iii) -15 ÷ 0 = 0

(iv) 0 ÷ 0 = 0

(v) (- 8) ÷ (- 1) = – 8

(vi) – 8 ÷ (- 2) = 4<

Solution:

(i) True

(ii) True

(iii) False

(iv) False

(v) False

(vi) True


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