RD Sharma Maths Solutions for Class 10 Chapter 9: Arithmetic Progressions
RD Sharma Class 10 Solution Chapter 9 Arithmetic Progressions: In this page, we will be discussing the solution of arithmetic progressions in class 9 chapter 9. We will also give you a few practice problems to help you understand the concept better. In this page we have given Chapter 9 all Exercise solution 9.1, 9.2, 9.3, 9.4, 9.5, 9.6.
The RD Sharma Solution for chapter 9 discusses problems related to the sequence of numbers. The questions and answers to Arithmetic Progressions are prepared under CBSE rules. Moreover, CBSE exam patterns are also taken into consideration by experts while designing the solutions to give a real image of the examination. Topics such as selection, general, and the terms of an Arithmetic Progression were prepared accurately in order to perform well in the examination. Students can study arithmetic progression, Sum of terms of Arithmetic progression, and General term of Arithmetic progression when going through the below exercises. RD Sharma Maths Solutions for Class 10 Chapter 9 Arithmetic Progressions is the best reference for class 10 when it comes to the CBSE board exam. The chapter-wise and exercise-wise both are available on this page. Take advantage of this opportunity and download the solution for the Arithmetic progression chapter now.
class 10 maths ch 9 arithmetic progression (2)Formulas use in Arithmetic Progression Maths:
List of Formulas used in Arithmetic Progression Maths problem are following below –
- Common difference of an AP: d = a2 – a1 = a3 – a2 = a4 – a3 = … = an – an-1
- nth term of an AP: an = a + (n – 1)d
- Sum of n terms of an AP: Sn = n/2(2a+(n-1)d) = n/2(a + l), where l is the last term of the arithmetic progression.
FAQ:
Define Arithmetic Progression.
Ans. Arithmetic progression is a list of numbers in which each term is obtained by adding a fixed number d to the preceding term, except the first term.
What is the formula of Arithmetic Progression?
Ans. Formulas are –
The sum of the first n terms of an AP is given by –
S = n/2 [2a + (n – 1) d ]
If l is the last term of the finite AP, say the nth term, then the sum of all terms of the AP is given by –
S = n/2 (a+ l)