New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 8 Probability Self Practice 14 Solution
(9) due to throwing diece, total possible outcome = { 1, 2, 3, 4, 5, 6 }
∴ p(s) = 6
For two dice, p(s) = 6 x 6 = 36
Favourable cases where the sum is 10 or more with 5 on 1st die = { (5, 5) (5, 6) }
∴ of getting the sum is 10 or more with 5 on 1st die = p(E) = 2
Probability of getting a sum of 10 or more with 5 on 1st die = p(E)/p(s) = 2/36 = 1/18
(10) num of outcomes of spinner = 10 = p(s)
(a) P(getting a multiple of 3) = p(E)/p(S) = 3/10
(b) p (getting a prime number) = p(E)/p(S) = 4/10 = 2/5
(c) p (not getting multiple of 2) = p(E)/p(S) = 5/10 = ½
(11) num of letters outcomes = 9 + 2 + 2 + 4 + 12 + 2 + 3 + 2 + 9 + 1 + 1 + 4 + 2 + 6 + 8 + 2 + 1 + 6 + 4 + 6 + 4 + 2 + 2 + 1 + 2 + 1 + 2
= 100
(a) P(‘O’ from full set) = P(E)/P(S) = 8/100 = 2/25
(b) Total num of all vowel = 9 + 12 + 9 + 8 + 4
= 42
Total num of all consonant = { (100 – 42) – blank}
= { 58 – 2 } = 56
Therefore, P(Consonant from the full set = P(E)/P(S)
= 56/100
= 28/50
Hiii sir
Ye two chapter itni late kyo Dale hai please tell me ….. please