**New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 8 Powers (Exponents) Self Practice 2a Solution**

**Evaluate**

**(1)** (a) 9^{0}

(b) (1/3)^{0}

(c) (-64/21)

(d) (395.008)^{0}

(e) (3xy/ab –z)

(f) 1/a^{0} + b^{0} + c^{0}

(g) (8^{0} – 2^{0})x 25^{0}

(h) (35^{0} + 2^{0} + 3^{0}) ÷ 3

**(2) Simplifying giving the answer as a fraction:**

(a) 6^{-1}

(b) 10^{-1}

(c) 4^{-3}

(d) 2^{-7}

(e) 3^{-3}

(f) p^{-1}

(g) (x^{-2})^{2}

(h) (10a)^{-2}

(i) (x + y)^{-2}

(j) (m^{5})^{-3}

**SOLUTION Number 1 & 2:**

**(3) Find the reciprocal of the following.**

(a) (3)^{-2}

(b) (-2)^{-5}

(c) (2/5)^{3}

(d) (2/3)^{-4}

**(4) Simplify and express the result in power notation with positive exponent.**

(a) (-2)^{-4} x (-2)^{-6}

(b) 3^{7} x 3^{-9} x 3^{6}

(c) 3^{7} x (3/5)^{-7}

(d) 2^{-7} x [(2)^{-3}]^{-4}

(f) (4^{-8} ÷ 4^{-10}) x 4^{-5}

**(5) Evaluate:**

(a) (8^{0} + 5^{-1}) x (1/5)^{-2}

(b) (30^{0} + 15^{0}) x (1/2)^{-3}

(c) (7^{-1} + 8^{-1} + 9^{-1}) ÷ (-1/9)^{-2}

(d) [(1/3)^{-2} + (1/4)^{-2} (1/6)^{-2}]

(e) {(-4/5)^{-2}}^{-2}

(f) 9^{-1} x 4^{3}/3^{-4}

(g) (5^{-1} x 4^{-1}) x (3/2)^{-2}

**SOLUTION Number 3, 4 & 5:**

**(6) Evaluate:**

(a) [(1/4)^{-1 }– (1/5)^{-1}] + 1

(b) [(11/12)^{-10} ÷ (11/12)^{-12} ] x 1-23/121

**(7) Find the value of m for which, 7 ^{2m} **

**÷ 7**

^{-4}= 7^{-6}**SOLUTION Number 6 & 7:**

Please can u explain me 2a ouestion ( 1 a)

when u make a negative exponent to positive u take the reciprocal of base and then make the exponent positive.

Hope this helps !!

Mental math batayae explain kar ke aur multiple choice bhi explain kar ke ok sir

Please can you explain mental maths question number 10

sure do it

Please explain question number 10 of its mental maths chapter 2

Ex.2A question 2g is wrong ans is 1/x⁴

4d I Can not understand

Please tell me clearly

Respected teacher,

Will you please upload the question and answers from the BOOK OF CLASS 8 COMPOSITE MATHS 2020, actually the questions are diffrent.

Please!

It would be a lot helpful!!