# New Learning Composite Mathematics Class 8 SK Gupta Anubhuti Gangal Line Graphs Chapter 15B Solution

## New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 8 Line Graphs Self Practice 15B Solution

(2)

(a) y = x + 5

 X 0 4 7 * y 5 9 12 *

(b) y = 2x

 X 1 3 6 y 2 6 12

(c) y = 2x – 3

 X 0 3 4 5 y -3 3 5 7

(d) y = x – 5

 X 5 8 9 11 y 0 3 4 6

(3)

(a) Y = 5X

 X 1 2 3 y 5 10 15

(b)

(i) X = 5

∴ Y = 5X =5 x 5 = 25

∴ Locate by going 5 positive units along the X axis & 25 positive units along the Y axis.

(ii) X = 6

∴ Y = 5X = 5 x 6 = 30

∴ Locate by going 6 positive units along the X axis & positive units along the Y axis.

(4)

 x 1 2 3 4 5 6 7 8 y 1.6 3.2 4.8 6.4 8 9.6 11.2 12.8

Here x is represents to mile.

Y is represents to km.

(a) 1 miles = 1.6 km

4.5 miles = (1.6 x 4.5) km

= 7.2 km

(b) 1.6 km = 1 miles

1 km = 1/ 1.6 miles

8 km = 1/ 1.6 x 8 miles

= 5 miles.

(5)

(b) Approximately 9.20 am

* Increasing

(c) 2 hours

(d) At 4 pm temperature will be -> 38.5oc

At 4 pm temperature will be -> 35oc

Tem fall = 38.5 – 35.0

= 3.5oc

(7)

(a) 2 cars

(b) (15 + 8 +10) = 33 cars are sold

(c) Sep & Oct

(8)

(a)

(i) Smiliti’s temperature at p.m. Saturday was 38.8oc

(ii) Smiti’s temperature at 8 am Sunady was 38.6o c

(iii) Smiti’s temperature at midnight Sunday 37.8o c

(iv) Smiti’s temperature at 12 h after midnight Sunday was 37.2oc

(b) The change in her temperature from 4 pm on Sunday to 4 am on Monday down 0 – 2o c

(c) Around noon Sunday, because of the sharp decrease in her temperature.

(9)

(a)

(i) Y -> 2500 (deposit)

X -> 160 + 240 / 2

= 400/2

= 200

S.I. = 200

(b) Yes, It is linear graph

(10)

(a) r = 42

C = 2πr

= 2 x 22/7 x 42

= 264

 r 7 14 21 28 35 42 c 44 88 132 176 220 264

(b) When,

C = 220 unit

∴ R = 35 Unit

Updated: August 31, 2020 — 3:17 pm