New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 7 Perimeter and Area Self Practice 14B Solution
(7) Area of the plot = (80 x 40) m2
= 3200 m2
Cost of the plot = Rs (3200 x 50000)
= Rs. 160000000
(8) Area of the tile = (25 x 20) cm2
= 500 cm2
Area of the floor = (12 x 9) cm2
= (1200 x 900) cm2
= 1080000 cm2
No of tiles required = 1080000/500
= 2160
(9) Area of the square handkerchief = (35)2 cm2
= 1225 cm2
3.5 m = 350 Cm
Total area of rectangular material = (70 x 350) cm2
= 24500 cm2
No of handkerchiefs = 24500/1225
=20
(10) Area of the floor = (6×9) m2
= 54 m2
Area of the rug = (4×7) m2
= 28 m2
Area of the floor not covered = (54-28) m2
= 26 m2
(11) Area of the small square = (13)2 cm2
= 169 cm2
Area of the larger square = (169+56) cm2
= 225 cm2
Therefore, Side length of the larger sq = √(225 ) m
= 15 m
(12) (a), (b) & (c)
(15)
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Please do double bar graph of this book ch 15 ex 15 D
HII
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