# New Learning Composite Mathematics Class 7 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14B Solution

## New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 7 Perimeter and Area Self Practice 14B Solution   (7) Area of the plot = (80 x 40) m2

= 3200 m2

Cost of the plot = Rs (3200 x 50000)

= Rs. 160000000

(8) Area of the tile = (25 x 20) cm2

= 500 cm2

Area of the floor = (12 x 9) cm2

= (1200 x 900) cm2

= 1080000 cm2

No of tiles required = 1080000/500

= 2160

(9) Area of the square handkerchief = (35)2 cm2

= 1225 cm2

3.5 m = 350 Cm

Total area of rectangular material = (70 x 350) cm2

= 24500 cm2

No of handkerchiefs = 24500/1225

=20

(10) Area of the floor = (6×9) m2

= 54 m2

Area of the rug = (4×7) m2

= 28 m2

Area of the floor not covered = (54-28) m2

= 26 m2

(11) Area of the small square = (13)2 cm2

= 169 cm2

Area of the larger square = (169+56) cm2

= 225 cm2

Therefore, Side length of the larger sq = √(225 ) m

= 15 m

(12) (a), (b) & (c)      (15)     1. 