**New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 7 Perimeter and Area Self Practice 14B Solution**

**(7)** Area of the plot = (80 x 40) m^{2 }

= 3200 m^{2 }

Cost of the plot = Rs (3200 x 50000)

= Rs. 160000000

**(8)** Area of the tile = (25 x 20) cm^{2}

= 500 cm^{2}

Area of the floor = (12 x 9) cm^{2}

= (1200 x 900) cm^{2}

= 1080000 cm^{2}

No of tiles required = 1080000/500

= 2160

**(9)** Area of the square handkerchief = (35)^{2 }cm^{2}

= 1225 cm^{2}

3.5 m = 350 Cm

Total area of rectangular material = (70 x 350) cm^{2 }

= 24500 cm^{2 }

No of handkerchiefs = 24500/1225

=20

**(10)** Area of the floor = (6×9) m^{2}

= 54 m^{2}

Area of the rug = (4×7) m^{2}

= 28 m^{2}

Area of the floor not covered = (54-28) m^{2}

= 26 m^{2}

**(11)** Area of the small square = (13)^{2 }cm^{2 }

= 169 cm^{2}

Area of the larger square = (169+56) cm^{2}

= 225 cm^{2}

Therefore, Side length of the larger sq = √(225 ) m

= 15 m

**(12) (a), (b) & (c)**

**(15)**

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Please do double bar graph of this book ch 15 ex 15 D