# New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Whole Numbers Chapter 2D Solution

## New Learning Composite Mathematics SK Gupta Anubhuti Gangal Class 6 Whole Numbers Self Practice 2D Solution

(1) (a) Parentheses

(b) Parentheses

(c) Multiplication

(e) Division

(f) Parentheses

(2) (a) 27 – 11 + 4

= 16 + 4

= 20

(b) (28 – 8) ÷ 4

= 20 ÷ 4

= 5

(c) 136 – 100 ÷ 5

= 136 – 20

= 116

(d) 80 – 35 x 2

= 80 – 70

= 10

(e) 20 + 15 ÷ 3 – 8

= 20 + 5 – 8

= 17

(f) 14 x (17 – 7) + 5

= 14 x 10 + 5

= 140 + 5

= 145

(g) 54 ÷ 9 + 3 x 5

= 6 + 3 x 5

= 6 + 15

= 21

(h) 60 – 8 x 12 ÷ 3

= 60 – 8 x 4

= 60 – 32

= 28

(i) 15 ÷ 3 x 5

= 5 x 5

= 25

(j) 18 ÷ (6 ÷ 3)

= 18 ÷ 2

= 9

(k) (20 ÷ 4) ÷ 5

= 5 ÷ 5

= 1

(l) 4 x 5 + 8 – 7

= 20 + 4 – 7

= 24 – 7

= 17

(m) 19 – 15 ÷ 5 – 16

= 19 – 3 – 16

= 16 – 16

= 0

(n) 8 x (7 – 2) ÷ 5 – 8

= 8 x 5 ÷ 5 – 8

= 8 x 1 – 8

= 8 – 8

= 0

(o) 72 ÷ (9 + 0 x 8) ÷ 8

= 72 ÷ (9 + 0) ÷ 8

= 72 ÷ 9 ÷ 8

= 8 ÷ 8

= 1

(3) (a) 24 – (8 ÷ 4 x 2) = 20

(b) 24 – 8 ÷ (4 x 2) = 23

(c) (24 – 8) ÷ 4 x 2 = 8

(d) (24 – 8 ÷ 4) x 2 = 44

(e) (7 + 2) x 6 – (4 -3) = 53

(f) 16 x (3 -2) ÷ 4 = 4

(g) 8 x (0 + 4) – 5 = 27

(h) 26 ÷ (5 + 8) x 7 = 14

(4) (a) 7 x 4 – 3

= 28 – 3

= 25

7 x (4 – 3)

= 7 x 1

= 7

7 x 4 – 3 > 7 x (4 – 3)

(b) 60 ÷ 5 x 4

= 12 x 4

= 48

60 ÷ (5 x 4)

= 60 ÷ 20

= 3

60 ÷ 5 x 4 > 60 ÷ (5 x 4)

(c) (8 + 12) ÷ 4

= 20 ÷ 4

= 50

8 + 12 ÷ 4

= 8 + 3

= 11

(8 + 12) ÷ 4 < 8 + 12 ÷ 4

(d) 23 – 18 + 7

= 5 + 7

= 12

15 ÷ 3 + 7

= 5 + 7

= 12

23 – 18  + 7 = 15 ÷ 3 + 7

(5) (a) (1025 ÷ 25) ÷ (205 ÷ 5)

= 41 ÷ 41

= 1

(b) (1500 ÷ 1500) x (165 ÷ 165)

= 1 x 1

= 1

Updated: October 31, 2020 — 12:55 pm