New Learning Composite Mathematics Class 6 SK Gupta Anubhuti Gangal Perimeter and Area Chapter 14A Solution
(1) (a) Perimeter = (3 + 5 + 6 + 2 + 7) unit
= 23
(b) DE = (10 – 6) unit
= 4
EF = (8 + 7) unit
= 15
∴ Perimeter = (8 + 6 + 7 + 4 + 15 + 10) unit
= 50
(c) PQ = 3 Unit
ST = 2 Unit
TU = 3 Unit
WL = 2 Unit
∴ Perimeter = (1+2+3+1+3+2+1+2+3+1+3+2) Unit
= 24 Unit
(d) FG = 5 unit
∴ Perimeter = (5+0.5+3+3+0.5+5+1) Unit
= 18 Unit
(e) ∴ Perimeter = (1+3+2+3+4+1+3+2+3+4+1+3+2+3+4+1+3+2+3+4) Unit
= 52 Unit
(2) According to statement
(7 + a + 5 + 9 + 4 + 16) = 53
Or, a = 53 – (7 + 5 + 9 + 4 + 16)
Or, a = 53 – 41
∴ = 12
Ans – 12m
(3) (a) Perimeter = (3 X 8) cm
= 24 cm
(b) Perimeter = (4 X 10) cm
= 40 cm
(c) Perimeter = (5 X 62) cm
= 31
(d) Perimeter = (6 X 9.5) cm
= 57 cm
(e) Perimeter = {(2 X 5) + 7} cm
= {10 + 7} cm
= 17 cm
(4) (a) Length at one side = 36.8/4 cm
= 9.2 cm
(b) Length of one side = 22.5/3 cm
= 7.5 cm
(c) Length of one side = 42.4/8 cm
5.3
(d) Length of one side = 25.2/4 cm
= 6.3
(5) (a) Length of each side = 48/4 cm
= 12 cm
(b) Length of each side = 48/3 cm
= 16
(c) Length of each side = 48/6 cm
= 8 cm
(6) 2a + 14 = 50
Or, 2a = 50 – 14
Or, 2a = 36
Or, a = 36/2
∴ a = 18
Ans – 18 cm
(7) (a) Perimeter of the rectangle = {2 (8+5)} cm
= 2 X 13
= 26
(b) Perimeter of the rectangle = {2 (10.7 + 7.3)} cm
{2 X 18} cm
= 36
(c) 90 mm = 9cm
∴ Perimeter of the rectangle = {2 (12+9)} cm
= {2 X 21} cm
= 42 cm
(d) 0.85m = 85 cm
∴ Perimeter of the rectangle = {2 (85 + 70} cm
= {2 X 155} cm
= 310 cm
= 3.10 m
(8) (a) Let, length of the rectangle be L
2 (L + 5) = 32
Or, 2L + 10 = 32
Or, 2L = 32 – 10
Or, 2L = 22
Or, L = 22/2
∴ L = 11
Ans – Length of the rectangle is 11 cm
(b) Let the breadth x
2 (x + 24) = 80
Or, 2x + 48 = 80
Or, 2x = 80 – 48
Or, 2x = 32
Or, x = 32/2
∴ x = 16
Ans – The breadth of the rectangle is 16 cm.
(9) Length of the rectangle = (15 X 3) cm
= 45
∴ Perimeter of the rectangle = (15 X 3) cm
= 45
∴ Perimeter = {2 (45 + 15)} cm
= 2 X 60 cm
= 120 cm
(10) Ratio of length and width = 5:3
Let, length = 5x
Width = 3x
2 (5x + 3x) = 112
Or, 2 X 8x = 112
Or, 8x = 112/2
Or, x = 112/2X8 = 7
∴ Length = (5 X 7) cm
= 35 cm
Width = (3 X 7) cm
= 21 cm
Ans – The length and the width of the rectangle is 35 cm, 21 cm.
(11) Perimeter of the square park = (4 X 80) cm
= 320 cm
Perimeter of the rectangle park = {2 X (65 + 55) cm
= {2 X 120} cm
= 240 cm
Ans – From runs greater distance.
(12) Perimeter = {2 (850 + 700)} m
= {2 X 1550} m
= 3100 cm
∴ Wires requires = (5 X 3100) m
= 15500 m
Then, cost of fencing = RS (15500 X 80)
= RS 1240000
Ans – length of the wire is 15500 m cost of fencing is RS 1240000.
