**New Learning Composite Mathematics Class 5 S.K. Gupta Anubhuti Gangal Fractions Chapter 7B Solutions**

New Learning Composite Mathematics Class 5 S.K. Gupta Anubhuti Gangal Fractions Chapter 7B Solutions by expert Math Teacher.

**(1) Add the following and give your answer in simplest form.**

**(a) 3/5 + 1/10**

= (6+10)/10 (LCM of 5 and 10 is 10)

= 16/10

= 8/5 (After simplify)

**(b) 2/3 + 1/9**

= (6+1)/9 (LCM of 3 and 9 is 9)

= 7/9

**(c) 5/9 + 2/3**

= (5+6)/9 (LCM of 9 and 3 is 3)

= 11/9

**(d) 5/12 + ½**

= (5+6)/12 (LCM of 12 and 2 is 12)

= 11/12

**(e) 5/16 + 7/18**

= (90+112)/288 (LCM of 16 and 18 is 288)

= 202/288

= 101/144 (After simplify)

**(f) 1/3 + ¼ + 1/12**

= (4+3+12)/12 (LCM of 3, 4 and 12 is 12)

= 19/12

**(g) 3/5 + 2/10 + ½**

= (6+2+5)/10 (LCM of 5, 10 and 2 is 10)

= 13/10

**(h) 3/5 + 2/15 + 3/10**

= (18+4+9)/30 (LCM of 5, 15 and 10 is 30)

= 31/30

**(i) 2/3 + ¾ + 9/12**

= (8 + 9 + 9)/12 (LCM of 3, 4 and 12 is 12)

= 26/12

= 13/6 (After Simplify)

**(j) 1/3 + 4/5 + 11/15**

= (5+12+11)/15 (LCM of 3, 5 and 15 is 15)

= 28/15

**(k) 5/14 + 19/21 + 47/84**

= (30+76+47)/84 (LCM of 14, 21 and 84 is 84)

= 153/84

**(2) Subtract the following and give your answer in simplest form.**

**(a) 2/3 – ¼**

= (8-3)/12 (LCM of 3 and 4 is 12)

= 5/12

**(b) 7/8 – 5/20**

= (35-10)/40 (LCM of 8 and 20 is 40)

= 25/40

= 5/8 (After simplify)

**(c) 9/10 – 11/20**

= (18-11)/20 (LCM of 10 and 20 is 20)

= 7/20

**(d) 11/12 – 2/9**

= (33-8)36 (LCM of 12 and 9 is 36)

= 26/36

= 13/18 (After simplify)

**(e) 5/12 – 3/16**

= (20 – 9)/48 (LCM of 12 and 16 is 48)

= 11/48

**(f) 4/14 – 4/21**

= (12 – 8)/42 (LCM of 14 and 21 is 42)

= 4/42

= 2/21 (After simplify)

**(g) 15/24 – 19/36**

= (45 – 38)/72 (LCM of 24 and 36 is 72)

= 7/72

**(h) 8/10 – 1/5 – ½**

= (8 – 2 – 5)/10 (LCM of 10, 5 and 2 is 10

= 1/10

**See: **