ML Aggarwal CBSE Solutions Class 8 Math 6th Chapter Percentage and its Applications Exercise 6.4
(1) (i) CP = 50/-
GST = 5% of 50
∴ = 5/100 X50
= 5/2 /-
∴ SP = 50 + 5/2
= 100+5/2
= 105/2 = 50.50/- (Ans)
(ii) 1kg = 150/-
∴ CP of 5kg = 150X5 = 750/-
∴ GST = 5% of CP
= 5/100 X750
= 37.5/-
∴ SP = 750 + 37.5
= 787.50/- (Ans)
(2) (i) Let , original price = x
∴ GST = 8% of x
= 8x/100 = 2x/25
According to question –
X + 2x/25 = 13500
Or, 25x + 2x/25 = 13500
Or, 27x/25 = 13500
Or, x = 13500X25/27
Or, x = 12500
∴ Original price = 12500/-
(ii) Let, original price = x
∴ GST = 8% x = 8x/10 = 2x/25
According to question –
X + 2x/25 = 180
Or, 25x + 2x/25 = 180
Or, 27x = 180 X 25
Or, x = 180X25/27 = 500/3 = 166.66/-
(3) SP = 34992
Let, CP = x
∴ GST = 8% of x = 8x/100 = 2x/25
According to question –
X + 2x/25 = 34992
Or, 25x + 2x/25 = 34992
Or, 27x = 34992 X 25
Or, x = 34992 X 25/37 = 32,400
∴ CP = 32,400 /- (Ans)
(4) SP = 1296/-
Original price = 1200/-
Let, GST = x% of 1200
= x/100 X1200 = 12x
According to question –
1200 + 12x = 1296
Or, 12x = 1296 – 1200 = 96
Or, x = 96/12 = 8
∴ GST = 8% (Ans)
(5) Let, CP = x
GST1 = 8% of x
= 8x/100 = 2x/25
Old SP = 523.80
According to qne –
X + 2x/25 = 523.80
Or, 25x + 2x/25 = 523.80
Or, 27x = 523.80 X 25
Or, x = 523.50 X 25/27 = 485
∴ CP = 485/-
Now, GST2 = 10% of 485
= 10/100 X485
∴ Now SP = 485 + 48.50
= 533.50/- (Ans)
(6) MP = 4800/-
Dis = 10%
∴ SP = 4800 X 90/100
= 4320/-
GST = 8% of SP
= 8/100 X 4320
= 345.6/-
∴ The paid amount = 4320 + 345.6
= 4665.60/- (Ans)
(7) MP = 10900/-
Let, the reduce price = x
∴ GST = 9% X x
= 9x/100
According to question –
X + 9x/100 = 10900
Or, 100x + 9x/100 = 10900
Or, 109x = 10900 X 100
Or, 109x = 10900 X 100
Or, x = 10900 X 100/109 = 10000
∴ Amount reduce = 10900 – 10000
= 900 /- (Ans)