ML Aggarwal CBSE Solutions Class 8 Math 6th Chapter Percentage and its Applications Exercise 6.3
(1) (i) MP = 575 /-
Dis = 12%
SP = 575 X 88/100
= 506/- (Ans)
Dis = 575 – 506 = 69/- (Ans)
(ii) MP = 12750/-
dis = 8 1/3 % = 25/3 %
SP = 12750 X (100 – 25/3)/100
= 12750 X (275/3)/100
= 1275 X 275/10 X 3
= 11687.5/-
Dis = 12750 – 11687.5
= 1062.5/-
(2) (i) MP = 780/-
SP = 721.50/-
Discount = 780 – 721.50
= 58.50/- (Ans)
Dis % = 58.50/780 X100 =
= 5850 X 100/100 X 780
= 7.5% (Ans)
(ii) AP = 28500/-
SP = 24510/-
∴ dis = 28500 – 24510
= 3990/- (Ans)
Dis % = 3990/28500 X100
= 14% (Ans)
(9) CP = 1600/-
(i) Let, MP = x
Given, CP price is 20% below the market price.
∴ According to qne –
(100-20)x/100 = 1600
Or, 80x/100 = 1600
Or, x = 1600X10/8 = 2000
∴ MP = 2000/- (Ans)
(ii) dis = 16%
∴ SP = 2000X84/100
= 1680/- (Ans)
(iii) Profit = 1680 – 1600
= 80/-
Profit % = 80/1600 X 100
= 5% (Ans)
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