**ML Aggarwal CBSE Solutions Class 6 Math First Chapter Knowing Our Numbers Exercise 1.4**

(1) Round off each of the following numbers to their nearest tens:

(i) 77 = 80

(ii) 903 = 900

(iii) 1205 = 1200

(iv) 999 = 1000

(2) Estimate each of the following numbers to their nearest hundreds:

(i) 1246 = 1200

(ii) 32057 = 32100

(iv) 53961 = 54000

(v) 555555 = 555600

(3) Estimate each of the following numbers to their nearest thousands:

(i) 5706 = 6000

(ii) 378 = 1000

(iii) 47599 = 48000

(iv ) 1,09736 = 110000

(4) Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):

(i) 439 + 334 + 4317

= 400 + 300 + 4300 (Nearest 100)

= 5000

439 + 334 + 4317

= 440 + 330 + 4320 (Nearest 10)

= 5090

(ii) 8325 – 491

= 8300 – 500 (Nearest 100)

= 7800

8325 – 491

= 8320 – 490 (Nearest 10)

= 7830

(iii) 108734 – 47599

= 108700 – 47600 (Nearest 100)

= 61100

108734 – 47599

= 108730 – 47600 (Nearest 10)

= 61130

(iv) 4,89,348 – 48,365

= 489300 – 48400 (Nearest 100)

= 440900

4,89,348 – 48,365

= 489350 – 48360 (Nearest 10)

= 440990

(5) Estimate each of the following by rounding off each number nearest to its greatest place:

(i) 730 + 998

= 700 + 1000

= 1700

(ii) 5290 + 17986

= 5000 + 20000

= 25000

(iii) 796 – 314

= 800 – 300

= 500

(iv) 28,292 – 21496

= 30000 – 20000

= 10000

(6) Estimate the following products by rounding off each of its factors nearest to its greatest place:

(i) 578 x 161

= 600 x 200

= 120000

(ii) 9650 x 27

= 10000 x 30

= 300000

(7) Estimate the following products by rounding off each of its factors nearest to its hundreds place.

(i) 5281 x 3491

= 5300 x 3500

= 18,550,000

(ii) 1387 x 888

= 1400 x 900

= 1,260,000

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