Mental Math Class 5 Worksheet – Factors and Multiples
Mental Math Class 5 Worksheet Chapter Number. Here in this page we have given total 25 Questions Set with Solution for Students.
(Q1) Find all factors of 12?
Solution:
Numbers which divisible to given number and no remainder is left is all factors of given number.
∴ Factors of 12 are 1, 2, 3, 4, 6 and 12.
(Q2) Which number is a factor of every numbers?
Solution:
1 is a number which is factor of every number.
(Q3) Find greatest factor of 36?
Solution:
The greatest factor of any number is number it self.
∴ Greatest factor of 36 is 36.
(Q4) How many prime numbers are in between 1 to 100?
Solution:
There are 25 prime numbers in between 1 to 100.
(Q5) Which least number should be added in 2585 to make it divisible by 3?
Solution:
Here, we have to apply divisibility test of 3.
We have to add all numbers and divide it by 3 is the divisibility test of 3.
2585/3 = 2+5+8+5/3 = 20/3
Here, we have to apply divisibility test of 3.
We have to add all number and divide it by 3 is the divisibility test of 3.
2585/3 = 2+5+8+5/3 = 20/3
Here, sum is 20 which is not divisible by 3.
∴ 1 is added to 2585 to make it divisible by 3.
(Q6) Find the product of 3rd multiple of 2 and 3?
Solution:
We 1st find,
3rd multiple of 2 = 2×3 = 6
3rd multiple of 3 = 3×3 = 9
∴ Product of 3rd multiple of 2 and 3 = 6×9 = 54
(Q7) Find the 10th multiple of 25?
Solution:
∴ We have to find 10th multiple of 25
∴ We have to do multiplication of 25 and 10
25×10 = 250
10th multiple of 25 = 250
(Q8) Which are the prime numbers which is less than 50?
Solution:
Prime numbers which are less than 50 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47
∴ There are 15 prime numbers less than 50.
(Q9) Find product fall common factors of number 10 and 16?
Solution:
1st we find factors of 10 and 16
Factors of 10 à 1, 2, 5, 10
Factors of 16 –> 1, 2, 4, 8, 16
The common factors of 10 and 16 is 1 and 2
∴ Product of common factor is 2×2 = 4
(Q10) Find least common multiple (LCM) of numbers 8 and 10?
Solution:
Here, we have to find LCM of 8 and 10
∴ The LCM of 8 and 10 is 2×4×5 = 40
(Q11) Find highest common factor (HCM) of number 10 and 20?
Solution:
We have to find HCF of 10 and 20.
∴ HCF of 10 and 20 is 5×2 = 10
(Q12) Find the multiple of 8 which lies between 70 and 80?
Solution:
Here, we have to find multiple of 8 which lies between 70 and 80.
We know, 8×9 = 72 which lies in 70 and 80
∴ The 9th multiple of 8 is lies between 70 and 80.
(Q13) Find least multiple of 8 and 13?
Solution:
Here, we have to find LCM or 8 and 13
There is no common factor of 8 and 13
∴ LCM of 8 and 13 is (13×8)
∴ LCM of 8 and 13 = 104
(Q14) Find highest common multiple of 8 and 9?
Solution:
We know, the HCF of two consecutive natural number is always 1.
∴ The HCF of 8 and 9 is 1.
(Q15) Which number is only a even prime number?
Solution:
2 is the only even prime number.
(Q16) Find value of ‘x’
Solution:
The given numbers are the multiple of 9.
We have to find 4th multiple of 9.
4×9 = 36
∴ x = 36
(Q17) Find ‘x’
Solution:
We know, 36 = 18×2
36 = 9×2×2
∴ x = 9
We split 18 as 9×2
(Q18) Certain choclates are arrange in number 8 and 12. Find least common multiple of choclates —
Solution:
Here, we have to find LCM of 8 and 12.
∴ LCM of 8 and 12 are 2×2×2×3 = 24
∴ The least common numbers of choclates is 24.
(Q19) Find all factors of 120?
Solution:
We have to find all factors of 120
Factors of 120 are 1, 2, 3, 4, 6, 8, 10, 12, 20, 24, 30, 40, 60 and 120
(Q20) Which number is neither composite nor prime number and is factor of every number.
Solution:
1 is the number which is neither composite nor prime number and is factor of ever numbers.
(Q21) Find sum o common factors of 20 and 30.
Solution:
1st we find factor of 20 and 30.
Factor of 20 à 1, 2, 4, 5, 10 and 20
Factor of 30 à 1, 2, 3, 5, 6, 10, 15 and 30
Common factors of 20 & 30 are 1, 2, 5 and 10
∴ Sum is 1+2+5+10 = 18
(Q22) Find highest common factor of 50 and 70?
Solution:
Here, we have to HCF of 50 and 75.
∴ HCF of 50 and 75 is 5×5 = 25
(Q23) 30m and 35m length ribbons are cut into equal length. Find the highest length of each piece?
Solution:
Given that,
There are 2 ribbons of 30m and 35m length.
We have to highest length each piece when cut into equal length.
∴ HCF of 30m & 35m
∴ The highest length of each piece is 5m
(Q24) Find the product of 2nd multiple of 12 and 5th multiple of 6?
Solution:
We find,
2nd multiple of 12 = 12×2 = 24
5th multiple of 6 = 6×5 = 30
∴ Product = 24×30
= 720
∴ Product of 2nd multiple of 12 and 5th multiple of 6 is 720.
(Q25) Find highest common factors of 12, 24 and 36?
Solution:
Here, we have to find HCF of 12, 24 and 36
∴ The HCF of 12, 24 and 36 is 2×3 = 6