Maha Board (MSBHSE) Class 8 Math (गणित) Compound interest Practice Set 14.1 Solution (Page No. 90) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 14: Compound interest (Practice Set 14.1).
Maharashtra Board Class 8 Math Practice Set 14.1 Solution | BalBharati Class 8 Mathematics Chapter 14 Solution:
Subject | Mathematics (गणित) |
Class | 8 (८) |
Chapter | 14 |
Practice Set | 14.1 |
Practice Set 14.1 Solution (Page No. 90)
(1) Find the amount and the compound interest.
No | Principal | Rate (p.c.p.a.) | Duration (years) |
1 | 2000 | 5 | 2 |
2 | 5000 | 8 | 3 |
3 | 4000 | 7.5 | 2 |
Solution:
(2) Sameerrao has taken a loan of Rs. 12500 at a rate of 12 p.c.p.a. for 3 years. If the interest is compounded annually then how many rupees should he pay to clear his loan?
(3) To start a business Shalaka has taken a loan of Rs. 8000 at a rate of 10-1/2 p.c.p.a. After two years how much compound interest will she have to pay?
Solution:
Latest Edition BalBharati Math Solution for Standard 8th Chapter 14.1. Any Kinds of problem to understand, Feel free to comment us below. Thank You.