Maha Board (MSBHSE) Class 8 Math (गणित) Area Practice Set 15.5 Solution (Page No. 102) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 15: Area (Practice Set 15.5).

**Maharashtra Board Class 8 Math Practice Set 15.5 Solution | BalBharati Class 8 Mathematics Chapter 15 Solution:**

Subject | Mathematics (गणित) |

Class | 8 (८) |

Chapter | 15 |

Practice Set | 15.5 |

**Practice Set 15.5 Solution (Page No. 102)**

**(1.) Find the areas of given plots. ( All measures are in metres.)**

Solution:

Here, △PAQ and △SCR are right angle triangles

and, □AQRC is a trapezium. Base and height of △PTS are given. Now let us find area

A(△AQP) = 1/2 x l(PA) x l(AQ)

= 1/2 x 30 x 50

= 750 sq m.

A(△RCS) = 1/2 x l(CS) x l(RC)

= 1/2 x 60 x 25

=750 sq m.

∴ A(□QACR) = 1/2 [l(AQ) + l(CR)] x l(AC)

= 1/2 [50 + 25] x (30 + 30)

= 1/2 x 75 x 60

= 2250 sq m.

∴l(PS) = l(PB) + l(BS) = 30 + 30 + 30 + 60 = 150 m

∴ A(△PTS) =1/2 x l(PS) x l(BT)

= 1/2 x 150 x 30

= 2250 sq m.

Area of Polygon, QPSTR

= A (△AQP + A (□QACR) +A (△RCS) + A (△PTS)

= 750 + 2250 + 750 + 2250

= 6000 sq m.

*Latest Edition BalBharati Math Solution for Standard 8^{th} Chapter 15.5. Any Kinds of problem to understand, Feel free to comment us below. Thank You.*