# Maharashtra Board Class 8 Math Area Chapter Practice Set 5 Solution

Maha Board (MSBHSE) Class 8 Math (गणित) Area Practice Set 15.5 Solution (Page No. 102) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 15: Area (Practice Set 15.5).

### Maharashtra Board Class 8 Math Practice Set 15.5 Solution | BalBharati Class 8 Mathematics Chapter 15 Solution:

 Subject Mathematics (गणित) Class 8 (८) Chapter 15 Practice Set 15.5

### Practice Set 15.5 Solution (Page No. 102)

(1.) Find the areas of given plots. ( All measures are in metres.) Solution:

Here, △PAQ and △SCR are right angle triangles
and, □AQRC is a trapezium. Base and height of △PTS are given. Now let us find area
A(△AQP) = 1/2 x l(PA) x l(AQ)
= 1/2 x 30 x 50
= 750 sq m.
A(△RCS) = 1/2 x l(CS) x l(RC)
= 1/2 x 60 x 25
=750 sq m.
∴ A(□QACR) = 1/2 [l(AQ) + l(CR)] x l(AC)
= 1/2 [50 + 25] x (30 + 30)
= 1/2 x 75 x 60
= 2250 sq m.
∴l(PS) = l(PB) + l(BS) = 30 + 30 + 30 + 60 = 150 m
∴ A(△PTS) =1/2 x l(PS) x l(BT)
= 1/2 x 150 x 30
= 2250 sq m.

Area of Polygon, QPSTR
= A (△AQP + A (□QACR) +A (△RCS) + A (△PTS)
= 750 + 2250 + 750 + 2250
= 6000 sq m.

Latest Edition BalBharati Math Solution for Standard 8th Chapter 15.5. Any Kinds of problem to understand, Feel free to comment us below. Thank You.

Updated: March 17, 2020 — 1:26 pm