# Maharashtra Board Class 8 Math Area Chapter Practice Set 4 Solution

Maha Board (MSBHSE) Class 8 Math (गणित) Area Practice Set 15.4 Solution (Page No. 101) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 15: Area (Practice Set 15.4).

### Maharashtra Board Class 8 Math Practice Set 15.4 Solution | BalBharati Class 8 Mathematics Chapter 15 Solution:

 Subject Mathematics (गणित) Class 8 (८) Chapter 15 Practice Set 15.4

Practice Set 15.4 Solution (Page No. 101)

(1) Sides of a triangle are cm 45 cm, 39 cm and 42 cm, find its area.

Solution: Area of a Triangle = 1/2 x base x height

Semiperimeter (S) = 1/2 (a + b + c)

Area of a triangle = √s(s-a)(s-b)(s-c)

This formula is known as Heron’s formula.

Sides of the triangle, a = 45 cm, b = 39 cm, c = 42 cm

∴ Semi perimeter (S) = 45 + 39 + 42/2

= 63 cm.

∴ Area = √s(s-a)(s-b)(s-c)

= √63(63-45)(63-39)(63-42)

= √63x18x24x21

= 756 Sq Cm Ans.

Latest Edition BalBharati Math Solution for Standard 8th Chapter 15.4. Any Kinds of problem to understand, Feel free to comment us below. Thank You.

Updated: March 16, 2020 — 3:36 pm