Maha Board (MSBHSE) Class 8 Math (गणित) Area Practice Set 15.4 Solution (Page No. 101) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 15: Area (Practice Set 15.4).
Maharashtra Board Class 8 Math Practice Set 15.4 Solution | BalBharati Class 8 Mathematics Chapter 15 Solution:
Practice Set 15.4 Solution (Page No. 101)
(1) Sides of a triangle are cm 45 cm, 39 cm and 42 cm, find its area.
Solution: Area of a Triangle = 1/2 x base x height
Semiperimeter (S) = 1/2 (a + b + c)
Area of a triangle = √s(s-a)(s-b)(s-c)
This formula is known as Heron’s formula.
Sides of the triangle, a = 45 cm, b = 39 cm, c = 42 cm
∴ Semi perimeter (S) = 45 + 39 + 42/2
= 63 cm.
∴ Area = √s(s-a)(s-b)(s-c)
= 756 Sq Cm Ans.
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