Maha Board (MSBHSE) Class 8 Math (गणित) Area Practice Set 15.1 Solution (Page No. 95) in our website. Here candidates of Marathi Medium & English Medium of Maharashtra State can follow this to get Most Easy Solution of Maharashtra Board Class 8 Chapter 15: Area (Practice Set 15.1).

**Maharashtra Board Class 8 Math Practice Set 15.1 Solution | BalBharati Class 8 Mathematics Chapter 15 Solution:**

Subject | Mathematics (गणित) |

Class | 8 (८) |

Chapter | 15 |

Practice Set | 15.1 |

**Practice Set 15.1 Solution (Page No. 95)**

(1) If base of a parallelogram is 18 cm and its height is 11 cm, find its area.

(2) If area of a parallelogram is 29.6 sq cm and its base is 8 cm, find its height.

**Solution: **

**(3) Area of a parallelogram is 83.2 sq cm. If its height is 6.4 cm, find the length of its base.**

**Solution:**

**Rules:
(1) Area of Square = Side x Side
(2) Area of Rectangle = Length x Breadth
(3) Area of Right Angled Triangle = 1/2 x Product of Sides making Right Angle.
(4) Area of Triangle = 1/2 x base x height
(5) Area of Parallelogram = base x height.**

*Latest Edition BalBharati Math Solution for Standard 8^{th} Chapter 15.1. Any Kinds of problem to understand, Feel free to comment us below. Thank You.*