# Maharashtra Board Class 7 Math Chapter 2 Multiplication and Division of Integers Solution

## Maharashtra Board Class 7 Math Solution Chapter 2 – Multiplication and Division of Integers

Balbharati Maharashtra Board Class 7 Math Solution Chapter 2: Multiplication and Division of Integers. Marathi or English Medium Students of Class 7 get here Multiplication and Division of Integers full Exercise Solution.

 Std Maharashtra Class 7 Subject Mathematics Solution Chapter Multiplication and Division of Integers

Practice Set 8

Multiply.

(i) (-5) × (-7)

ANS:

When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.

(-ve number) × (-ve number) = (+ve number)

(-5) × (-7) = 35

(ii) (-9) × (6)

ANS:

When there is product of one positive (+ve) and one negative (-ve) integerthe result we get is a negative integer.

(-ve number) × (+ve number) = (-ve number)

(-9) × (6) = -54

(iii) (9) × (-4)

ANS:

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(+ve number) × (-ve number) = (-ve number)

(9) × (-4) = -36

(iv) (8) × (-7)

ANS:

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(+ve number) × (-ve number) = (-ve number)

(8) × (-7) = -56

(v) (-124) × (-1)

ANS:

When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.

(-ve number) × (-ve number) = (+ve number)

(-124) × (-1) = 124

(vi) (-12) × (-7)

ANS:

When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.

(-ve number) × (-ve number) = (+ve number)

(-12) × (-7) = 84

(vii) (-63) × (-7)

ANS:

When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.

(-ve number) × (-ve number) = (+ve number)

(-63) × (-7) = 441

(viii) (-7) × (15)

ANS:

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(-ve number) × (+ve number) = (-ve number)

(-7) × (15) = -105

Practice Set 9

1.) Solve:

(i) (- 96) ÷ 16

ANS:

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

(- 96) ÷ 16 = -6

(ii) 98 ÷ (- 28)

ANS:

We write it as -98 ÷ 28

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

We divide both by 14 we get,

= -7/2

(iii) (- 51) ÷ 68

ANS:

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

We divide both by 17 we get,

= -3/4

(iv) 38 ÷ (- 57)

ANS:

We write it as -38 ÷ 57

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

We divide both by 19 we get,

= -2/3

(v) (- 85) ÷ 20

ANS:

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

We divide both by 5 we get,

= -17/4

(vi) (-150) ÷ (- 25)

ANS:

When there is two negative integers then the quotient of two negative integers is a positive number.

(-150) ÷ (- 25)

We write it as 150 ÷ 25

We divide both by 25 we get,

=6

(vii) 100 ÷ 60

ANS:

When there is twopositive integers the quotient of two positive integers is a positive number.

100 ÷ 60

We divide both by 20 we get,

= 5/3

(viii) 9 ÷ (- 54)

ANS:

We write it as -9÷ 54

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

We divide both by 9 we get,

= -1/6

(ix) 78 ÷ 65

ANS:

When there is two positive integers the quotient of two positive integers is a positive number.

78 ÷ 65

We divide both by 13 we get,

= 6/5

(x) (- 5) ÷ (- 315)

ANS:

When there is two negative integers then the quotient of two negative integers is a positive number.

(-5) ÷ (- 315)

We write it as 5 ÷ 315

We divide both by 5 we get,

=1/63

2.) Write three divisions of integers such that the fractional form of each will be 24/5.

ANS:

We write integers in such a way that the fractional form of each will be 24/5.

We multiply this form by 1, 2,3 etc.

24 x 2 /5 x 2 = 48/10

24 x 3 /5 x 3 = 72 / 15

24 x 5 / 5 x 5 = 120 /25

3.) Write three divisions of integers such that the fractional form of each will be -5/7.

ANS:

We write integers in such a way that the fractional form of each will be-5/7.

We multiply this form by 1, 2, 3 etc.

-5 x 2 /7 x 2 = -10 / 14

-5 x 3 /7 x 3= -15/21

-5 x 4 /7 x 4 = -20 / 28

4) The fish in the pond below, carry some numbers. Choose any 4 pairs and carry out four multiplications with those numbers. Now, choose four other pairs and carry out divisions with these numbers.

ANS:

Here fishes in the pond. They carry number with it.

We first perform multiplication of that numbers.

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(-ve number) × (+ve number) = (-ve number)

-13 x 9 = – 117

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(-ve number) × (+ve number) = (-ve number)

-15 x – 13 = 195

When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.

(-ve number) × (+ve number) = (-ve number)

9 x -8 = – 72

12 x 9 = 108

Now we make pairs of division of integers.

When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.

= -13 ÷ 9

= -15 ÷ (-13)

= 9 ÷ (-8)

When there is two positive integers the quotient of two positive integers is a positive number.

12 ÷ 9 = 4/3

Updated: July 2, 2021 — 1:16 am