Maharashtra Board Class 7 Math Solution Chapter 2 – Multiplication and Division of Integers
Balbharati Maharashtra Board Class 7 Math Solution Chapter 2: Multiplication and Division of Integers. Marathi or English Medium Students of Class 7 get here Multiplication and Division of Integers full Exercise Solution.
|
Std |
Maharashtra Class 7 |
| Subject |
Mathematics Solution |
|
Chapter |
Multiplication and Division of Integers |
Practice Set 8
Multiply.
(i) (-5) × (-7)
ANS:
When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.
(-ve number) × (-ve number) = (+ve number)
(-5) × (-7) = 35
(ii) (-9) × (6)
ANS:
When there is product of one positive (+ve) and one negative (-ve) integerthe result we get is a negative integer.
(-ve number) × (+ve number) = (-ve number)
(-9) × (6) = -54
(iii) (9) × (-4)
ANS:
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(+ve number) × (-ve number) = (-ve number)
(9) × (-4) = -36
(iv) (8) × (-7)
ANS:
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(+ve number) × (-ve number) = (-ve number)
(8) × (-7) = -56
(v) (-124) × (-1)
ANS:
When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.
(-ve number) × (-ve number) = (+ve number)
(-124) × (-1) = 124
(vi) (-12) × (-7)
ANS:
When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.
(-ve number) × (-ve number) = (+ve number)
(-12) × (-7) = 84
(vii) (-63) × (-7)
ANS:
When there is product of two negative (-ve) integers the result we get is a positive (+ve) integer.
(-ve number) × (-ve number) = (+ve number)
(-63) × (-7) = 441
(viii) (-7) × (15)
ANS:
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(-ve number) × (+ve number) = (-ve number)
(-7) × (15) = -105
Practice Set 9
1.) Solve:
(i) (- 96) ÷ 16
ANS:
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
(- 96) ÷ 16 = -6
(ii) 98 ÷ (- 28)
ANS:
We cannot write negative sign in denominator of any fraction.
We write it as -98 ÷ 28
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
We divide both by 14 we get,
= -7/2
(iii) (- 51) ÷ 68
ANS:
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
We divide both by 17 we get,
= -3/4
(iv) 38 ÷ (- 57)
ANS:
We cannot write negative sign in denominator of any fraction.
We write it as -38 ÷ 57
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
We divide both by 19 we get,
= -2/3
(v) (- 85) ÷ 20
ANS:
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
We divide both by 5 we get,
= -17/4
(vi) (-150) ÷ (- 25)
ANS:
When there is two negative integers then the quotient of two negative integers is a positive number.
(-150) ÷ (- 25)
We write it as 150 ÷ 25
We divide both by 25 we get,
=6
(vii) 100 ÷ 60
ANS:
When there is twopositive integers the quotient of two positive integers is a positive number.
100 ÷ 60
We divide both by 20 we get,
= 5/3
(viii) 9 ÷ (- 54)
ANS:
We cannot write negative sign in denominator of any fraction.
We write it as -9÷ 54
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
We divide both by 9 we get,
= -1/6
(ix) 78 ÷ 65
ANS:
When there is two positive integers the quotient of two positive integers is a positive number.
78 ÷ 65
We divide both by 13 we get,
= 6/5
(x) (- 5) ÷ (- 315)
ANS:
When there is two negative integers then the quotient of two negative integers is a positive number.
(-5) ÷ (- 315)
We write it as 5 ÷ 315
We divide both by 5 we get,
=1/63
2.) Write three divisions of integers such that the fractional form of each will be 24/5.
ANS:
We write integers in such a way that the fractional form of each will be 24/5.
We multiply this form by 1, 2,3 etc.
24 x 2 /5 x 2 = 48/10
24 x 3 /5 x 3 = 72 / 15
24 x 5 / 5 x 5 = 120 /25
3.) Write three divisions of integers such that the fractional form of each will be -5/7.
ANS:
We write integers in such a way that the fractional form of each will be-5/7.
We multiply this form by 1, 2, 3 etc.
-5 x 2 /7 x 2 = -10 / 14
-5 x 3 /7 x 3= -15/21
-5 x 4 /7 x 4 = -20 / 28
4) The fish in the pond below, carry some numbers. Choose any 4 pairs and carry out four multiplications with those numbers. Now, choose four other pairs and carry out divisions with these numbers.
ANS:
Here fishes in the pond. They carry number with it.
We first perform multiplication of that numbers.
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(-ve number) × (+ve number) = (-ve number)
-13 x 9 = – 117
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(-ve number) × (+ve number) = (-ve number)
-15 x – 13 = 195
When there is product of one positive (+ve) and one negative (-ve) integer the result we get is a negative integer.
(-ve number) × (+ve number) = (-ve number)
9 x -8 = – 72
12 x 9 = 108
Now we make pairs of division of integers.
When there is a positive integer and a negative integer then the quotient of a positive integer and a negative integer is always a negative number.
= -13 ÷ 9
= -15 ÷ (-13)
= 9 ÷ (-8)
When there is two positive integers the quotient of two positive integers is a positive number.
12 ÷ 9 = 4/3
2nd chapter 2.2 exercise
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