# Maharashtra Board Class 7 Math Chapter 11 Circle Solution

## Maharashtra Board Class 7 Math Solution Chapter 11 – Circle

Balbharati Maharashtra Board Class 7 Math Solution Chapter 11: Circle. Marathi or English Medium Students of Class 7 get here Circle full Exercise Solution.

 Std Maharashtra Class 7 Subject Math Solution Chapter Circle

### Practice Set 42

1.) Complete the table below.

ANS:

i)

Given that,

Radius of circle = 7 cm.

We know,

Diameter of circle = 2 x Radius.

Diameter of circle = 2 x 7

Diameter of circle = 14 cm.

Circumference of circle = π x Diameter.

Circumference of circle =π x 14

WE know,

Value of π = 22/7

Circumference of circle =22/7 x 14

Circumference of circle = 44 cm.

ii) Given that,

Diameter of circle = 28 cm.

We know,

Diameter of circle = 2 x Radius.

Radius of circle = Diameter / 2

Radius of circle = 28 / 2

Radius of circle = 14 cm.

Now,

Circumference of circle = π x Diameter.

Circumference of circle = π x 28

WE know,

Value of π = 22/7

Circumference of circle = 22/7 x 28

Circumference of circle = 88 cm.

iii) Given that,

Circumference of circle = 616 cm

Circumference of circle = π x Diameter.

WE know,

Value of π = 22/7

Diameter of circle =Circumference of circle x 7 / 22

Diameter of circle = 616 x 7 / 22

Diameter of circle = 28 x 7

Diameter of circle = 196 cm

We know,

Diameter of circle = 2 x Radius.

Radius of circle = Diameter / 2

Radius of circle = 196 / 2

Radius of circle = 98 cm.

iv) Given that,

Circumference of circle = 72.6 cm

Circumference of circle = π x Diameter.

WE know,

Value of π = 22/7

Diameter of circle = Circumference of circle x 7 / 22

Diameter of circle = 72.6 x 7 / 22

Diameter of circle = 3.3 x 7

Diameter of circle = 23 cm

We know,

Diameter of circle = 2 x Radius.

Radius of circle = Diameter / 2

Radius of circle = 23 / 2

Radius of circle = 11.5 cm.

2.) If the circumference of a circle is 176 cm, find its radius.

ANS:

Given that,

Circumference of a circle is 176 cm

Circumference of circle = π x Diameter.

WE know,

Value of π = 22/7

Diameter of circle = Circumference of circle x 7 / 22

Diameter of circle = 176 x 7 / 22

Diameter of circle = 8 x 7

Diameter of circle = 56 cm

We know,

Diameter of circle = 2 x Radius.

Radius of circle = Diameter / 2

Radius of circle = 56 / 2

Radius of circle = 28 cm.

3.) The radius of a circular garden is 56 m. What would it cost to put a 4-round fence around this garden at a rate of 40 rupees per metre?

ANS:

Given that,

The radius of a circular garden is 56 m.

We have to find its circumference to fence around this garden at a rate of 40 rupees per metre.

We know,

Diameter of circle = 2 x Radius.

Diameter of circle = 2 x 56

Diameter of circle = 112 m.

Circumference of circle = π x Diameter.

Circumference of circle = π x 112

WE know,

Value of π = 22/7

Circumference of circle = 22/7 x 112

Circumference of circle = 22 x 16

Circumference of circle = 352 m.

We have to fence 4 round of garden.

352 m x 4 = 1408 m

We have to find cost of 4-round fence around garden at a rate of 40 rupees per metre.

1408 m x 40 = Rs.56, 320

Cost of 4-round fence around garden at a rate of 40 rupees per metre is Rs.56, 320

4.) The wheel of a bullock cart has a diameter of 1.4m. How many rotations will the wheel complete as the cart travels 1.1 km?

ANS:

Given that,

The wheel of a bullock cart has a diameter of 1.4 m.

We have to find total number of rotation of wheels to travel distance of 1.1 km.

Diameter of wheel = 1.4 m

We have to find first the circumference of a wheel.

Circumference of a wheel = π x Diameter.

Circumference of circle = π x 1.4 m

WE know,

Value of π = 22/7

Circumference of circle = 22/7 x 1.4

Circumference of circle = 22 x 0.2

Circumference of circle = 4.4 m.

Number of wheel Rotations= Total Distance / Circumference of wheel

Number of wheel Rotations = 1100 m / 4.4 m

Number of wheel Rotations = 250

250 rotations of the wheel complete as the cart travels 1.1 km.

### Practice Set 43

1.) Choose the correct option.

If arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 120° then m(arc AYB) = ____

ANS:

We know,

Measure of circle = 3600

Given that,

Measure of minor arc m(arc AXB) = 120°

We have to find measure of major arc m(arc AYB).

Measure of major arc m(arc AYB) = 3600 – Measure of minor arc m(arc AXB)

Measure of major arc m(arc AYB) =3600 -120°

Measure of major arc m(arc AYB) = 240°

2.) Some arcs are shown in the circle with centre ‘O’. Write the names of the minor arcs, major arcs and semi-circular arcs from among them.

ANS:

Given that,

Circle having centre o.

We have to find names of the minor arcs, major arcs and semi-circular arcs.

Minor arcs =

The smaller part of circle is called minor arc when a chord divides the circle.

Arc PXQ

Arc PR

Arc RY

Arc XP

Arc XQ

Arc QY

Major arcs =

The Larger part of circle is called major arc when a chord divides the circle.

Arc PYQ

Arc PQR

Arc RQY

Arc XQP

Arc QRX

Semi-circular arcs =

When a chord or diameter of circle divides the circle in two equal parts then arc formed is semi-circular arc.

Arc QPR

Arc QYR

3.)  In a circle with centre O, the measure of a minor arc is 110°. What is the measure of the major arc PYQ?

ANS:

Given that,

Measure of a minor arc PXQ is 110°

We have to find measure of major arc PYQ.

We know,

Measure of circle = 3600

Measure of minor arc m (arc PXQ) = 110°

We have to find measure of major arc m (arc PYB).

Measure of major arc m (arc PYQ) = 3600 – Measure of minor arc m (arc PXQ)

Measure of major arc m (arc PYQ) = 3600 – 110°

Measure of major arc m (arc PYQ) = 250°

Updated: August 3, 2021 — 12:10 am